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3 years ago

Help please can’t get this wrong. Am I doing this right if not correct me. And how do I write it

Mathematics

2 answers:

Hunter-Best [27]3 years ago

7 0

Answer:

<-7/2 or a>1

i dunno how to explain i just got it.

zhannawk [14.2K]3 years ago

4 0

Answer:

a<-7/2 or a>1

Step-by-step explanation:

2a+5<-2 or -4a-1<-5

2a<-2-5 -4a<-5+1

2a<-7. -4a<-4

2a/2<-7/2 -4a/-4<-4/-4

a<-7/2 a>1

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Morgan’s grandmother orders her groceries online and has them delivered to her house. Her bill is $120. She has a coupon for 20%

iragen [17]

Answer:

The total price of the groceries, including discount and tip is $110.4.

Step-by-step explanation:

Here, the bill amount of groceries = $120

Now, the coupon off = 20%

Calculating the discount, we get

20% of bill amount $120 = 20% of 120 = $\frac{20}{100} \times 120 = 24$

So, the 20% discount on the bill amount = $24

The actual payable amount = Bill Amount - Discount

= $120 - $24 = $96

Now, 15% tip is also applied on the actual payable amount $96.

15% of 96 = $\frac{15}{100} \times 96 = 14.4$

So, the total price t = Payable amount + Tip amount

= $96 + $14.4 = $110.4

or, t = $110.4

Hence, the total price of the groceries, including the discount and the tip is t = $110.4.

6 0

2 years ago

Is the binomial a factor of the polynomial function?

olchik [2.2K]

Answer:

YES

Step-by-step explanation:

The given polynomial is: $f(x) = x^3 + 4x^2 - 25x - 100$

(x - a) is a factor of a polynomial iff x = a is a solution to the polynomial.

To check if (x - 5) is a factor of the polynomial f(x), we substitute x = 5 and check if it satisfies the equation.

∴ f(5) = 5³ + 4(5)² - 25(5) - 100

= 125 + 100 - 125 - 100

= 225 - 225

= 0

We see, x = 5 satisfies f(x). So, (x - 5) is a factor to the polynomial.

Now, to check (x + 2) is a factor.

i.e., to check x = - 2 satisfies f(x) or not.

f(-2) = (-2)³ + 4(-2)² - 25(-2) - 100

= -8 + 16 + 50 - 100

= -108 + 66

≠ 0

Therefore, (x + 2) is not a factor of f(x).

To check (x - 4) is a factor.

∴ f(4) = 4³ + 4(4)² - 25(4) - 100

= 64 + 64 - 100 - 100

= 128 - 200

≠ 0

Therefore, (x - 4) is not a factor of f(x).

7 0

2 years ago

A sample of 200 observations from the first population indicated that x1 is 170. A sample of 150 observations from the second po

igor_vitrenko [27]

Answer:

a) For this case the value of the significanceis $\alpha=0.05$ and $\alpha/2 =0.025$ , we need a value on the normal standard distribution thataccumulates 0.025 of the area on each tail and we got:

$z_{\alpha/2} =1.96$

If the calculated statistic $|z_{calc}| >1.96$ we can reject the null hypothesis at 5% of significance

b) Where $\hat p=\frac{X_{1}+X_{2}}{n_{1}+n_{2}}=\frac{170+110}{200+150}=0.8$

c) $z=\frac{0.85-0.733}{\sqrt{0.8(1-0.8)(\frac{1}{200}+\frac{1}{150})}}=2.708$

d) Since the calculated value satisfy this condition 2.708>1.96 we have enough evidence at 5% of significance that we have a significant difference between the two proportions analyzed.

Step-by-step explanation:

Data given and notation

$X_{1}=170$ represent the number of people with the characteristic 1

$X_{2}=110$ represent the number of people with the characteristic 2

$n_{1}=200$ sample 1 selected

$n_{2}=150$ sample 2 selected

$p_{1}=\frac{170}{200}=0.85$ represent the proportion estimated for the sample 1

$p_{2}=\frac{110}{150}=0.733$ represent the proportion estimated for the sample 2

$\hat p$ represent the pooled estimate of p

z would represent the statistic (variable of interest)

$p_v$ represent the value for the test (variable of interest)

$\alpha=0.05$ significance level given

Concepts and formulas to use

We need to conduct a hypothesis in order to check if is there is a difference between the two proportions, the system of hypothesis would be:

Null hypothesis: $p_{1} = p_{2}$

Alternative hypothesis: $p_{1} \neq p_{2}$

We need to apply a z test to compare proportions, and the statistic is given by:

$z=\frac{p_{1}-p_{2}}{\sqrt{\hat p (1-\hat p)(\frac{1}{n_{1}}+\frac{1}{n_{2}})}}$ (1)

a.State the decision rule.

For this case the value of the significanceis $\alpha=0.05$ and $\alpha/2 =0.025$ , we need a value on the normal standard distribution thataccumulates 0.025 of the area on each tail and we got:

$z_{\alpha/2} =1.96$

If the calculated statistic $|z_{calc}| >1.96$ we can reject the null hypothesis at 5% of significance

b. Compute the pooled proportion.

Where $\hat p=\frac{X_{1}+X_{2}}{n_{1}+n_{2}}=\frac{170+110}{200+150}=0.8$

c. Compute the value of the test statistic.

z-test: Is used to compare group means. Is one of the most common tests and is used to determine whether the means of two groups are equal to each other.

Replacing in formula (1) the values obtained we got this:

$z=\frac{0.85-0.733}{\sqrt{0.8(1-0.8)(\frac{1}{200}+\frac{1}{150})}}=2.708$

d. What is your decision regarding the null hypothesis?

Since the calculated value satisfy this condition 2.708>1.96 we have enough evidence at 5% of significance that we have a significant difference between the two proportions analyzed.

5 0

2 years ago

What is the value of x-6

Arlecino [84]

3x - 8 = -2 |subtract 10 from both sides

3x - 18 = -12 |divide both sides by 3

x - 6 = -4

7 0

2 years ago

2. Suppose over several years of offering AP Statistics, a high school finds that final exam scores are normally distributed wit

nirvana33 [79]

Answer:

By the Central Limit Theorem, the mean is 78, the standard deviation is $s = \frac{6}{\sqrt{n}}$ and the shape is approximately normal.

Step-by-step explanation:

Central Limit Theorem

The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean $\mu$ and standard deviation $\sigma$ , the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean $\mu$ and standard deviation $s = \frac{\sigma}{\sqrt{n}}$ .