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serious [3.7K]
3 years ago
7

Ricardo and John start swimming from the same location. Ricardo starts 15 seconds before John and swims at a rate of 3 feet per

second. John swims at a rate of 4 feet per second in the same direction as Ricardo. which equation could you solve to find how long it would take John to catch up with Ricardo?
A. 4t+3=3t
B. 4t+60=3t
C. 3t+3=4t
D. 3t+45=4t
Mathematics
1 answer:
laila [671]3 years ago
3 0
Speed=distance / time; ⇒distance=speed *  time
Distance traveled by Ricardo
Distance (Ricardo)= (3 ft / s) * 15s+3 ft/s * time=45 ft+3 ft/s*t=45+3t

Distance traveled by John:
Distance(John)=(4 ft/s) * time=4t

Distance traveled by Ricardo=Distance traveled by John
3t+45=4t

Answer: D.  3t+45=4t
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What are the solutions of the quadratic equation? 4x^2+34x+60=0
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