6,50g of ZnSO4 is 0,04 moles
Mass
of ZnSO4 :
m=6,50g
<span>Molar
mass of ZnSO<span>4 : </span></span>
M=M(Zn)+M(S)+4*M(O)
M=65,38
g/mol+32,06 g/mol+4*15,99 g/mol
M=161,40 g/mol
Molarity of ZnSO4 :
n=m/M
n=6,50g/161,40g/mol
n=0,04 mol
Ethanol is produced by the fermentation of the sugar of plants and it can be used as a fuel
in brasil they have a mass culture of using ethanol mixed with other hydrocarbons called biofuel
hope that helps
Answer:
12 moles of CO
Explanation:
According to Avogadro, one mole of a substance, contains the same number of elementary entities as 12g of carbon-12. Now the number of elementary entities (atoms, molecules, ions, particles etc) in any substance is given by the Avogadro's constant.
Now since 1 mole of a substance contains Avogadro's number of atoms, it means that the substance with the highest number of moles will have the highest number of atoms.
With this in mind we can see that 12 moles of CO is expected to contain 72.24 ×10^23 atoms of CO. Hence the answer.
I think you want to ask about Keq. At equilibrium, we can know [SO2Cl2] is 2.2*10-2 M -1.3*10-2M=9*10^-3 M. And [SO2]=[Cl2]. So the Keq=1.88*10^-2.