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3241004551 [841]
3 years ago
9

Biphenyl, C12H10,C12H10, is a nonvolatile, nonionizing solute that is soluble in benzene, C6H6.C6H6. At 25 ∘C,25 ∘C, the vapor p

ressure of pure benzene is 100.84 Torr. What is the vapor pressure of a solution made from dissolving 19.2 g19.2 g of biphenyl in 33.7 g33.7 g of benzene?
Chemistry
1 answer:
cestrela7 [59]3 years ago
8 0

Answer:

Vapour pressure of solution is 78.151 torr

Explanation:

Molar mass of biphenyl = 154.21 g

Molar mass of benzene = 78.11 g

19.2 g biphenyl = (19.2/154.21) moles of biphenyl = 0.125 moles of biphenyl

33.7 g of benzene = (33.7/78.11) moles of benzene = 0.431 moles of benzene

Total number of moles = (0.125+0.431) moles = 0.556 moles

Mole fraction of benzene in solution = (0.431/0.556) = 0.775

According to Roults law, vapour pressure of solution made from non-volatile solute = (mole fraction of solvent in solution)\times (vapour pressure of pure solvent)

Here solute is biphenyl and solvent is benzene

So, vapour pressure of solution = (0.775\times 100.84)torr = 78.151 torr

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Inga [223]

Answer:

There are a couple different types of precipitation, though it is generally taken to mean a synonym for rain. It includes rain, snow, sleet, and hail. With the increase in global warming, there is more precipitation. In general, the type of precipitation varies with the season; we see less in the summer of all types, more snow, sleet, and hail in the winter, and more rain in the temperate seasons like fall.

5 0
3 years ago
Consider the following reaction, which is spontaneous at room temperature. C3H8(g) + 5O2(g) → 3CO2(g) + 4H2O(g) Is ΔS positive o
Ugo [173]

Answer:

∆H = negative and ∆S = positive.

Explanation:

The reaction given in the question is spontaneous at room temperature ,

hence ,

The the gibbs free energy , i.e. ,∆G will be negative for  spontaneous reaction

According to the formula ,

∆G = ∆H -T∆S

The value of ∆G can be negative , if  ∆H has a negative value and  ∆S has a positive value , because , T∆S  , has a negative sign .

Hence , the answer will be , ∆H = negative and ∆S = positive.

3 0
3 years ago
Calcular la normalidad de 1 Kg de sulfuro de aluminio en 5000 ml de solucion.
Troyanec [42]

Calculate the normality of 1 Kg of aluminum sulfide in 5000 ml of solution.

Normality comes out to be 8.11

<h3> Given </h3>
  • Mass of solute: 1000g
  • Volume of solution (V): 5000 ml = 5 liters
  • Equivalent mass of solute (E) = molar mass / n-factor

n-factor for Al_{2}S_{3} is 6 and molar mass is 148g

So, on calculating equivalent mass is equal to 24.66g

FORMULAE of Normality (N) = (Mass of the solute) / (Equivalent mass of the solute (E) × Volume of the solution (V)

                                           N=\frac{1000}{24.66*5}

                                          <u> N=8.11</u>

Therefore, normality of 1 kg aluminum sulfide is 8.11

Learn more about normality here brainly.com/question/25507216

#SPJ10

7 0
2 years ago
A compound of carbon and hydrogen contains 92.3 percent c and has a molar mass of 78.1g/mol. What is its molecular
alekssr [168]

Answer:

C₆H₆

Explanation:

We need to find the molecular formula of a compound of carbon (C) and hydrogen (H), so what <em>we need to find out is the number of atoms of C and of  H in the molecule.</em> We know:

  • molar mass = 78.1 g/mol
  • C% = 92.3% = 92.3 g C / 100 g compound

So, in 1 mol of compound, 92.3% of the mass corresponds to Carbon:

<u>mass of C / mol of compound</u> = molar mass × C% = 78.1 g/mol × 92.3/100 = <u>72.1 g/mol</u>

<u>moles of C</u> = mass C / molar mass C = 72.1 g / 12.011 g/mol

moles of C = 6 moles of C per mol of compound

If 72.1 g in a mol of compound are Carbon atoms, the difference between the molar mass and the mass of Carbon atoms will correspond to H atoms in 1 mol of compound:

<u>mass of H / mol of compound</u> = molar mass - mass of C/mol

mass of H = 78.1 g / mol - 72.1 g /mol = <u>6.0 g/mol of compound</u>

<u>moles of H</u> = mass H / molar mass H = 6.0 g / 1.008 g/mol

moles of H = 6.0 moles of H per mol of compound

<em>So</em><em> one mol of compound has 6 moles of C and 6 moles of H.</em>

The molecular formula is then written as C₆H₆

7 0
3 years ago
The gas pressure in an aerosol can is 1.8 atm at 25°c. if the gas is an ideal gas, what pressure would develop in the can if it
Ratling [72]
For ideal gases at constant volume, you can use the law of Gay - Lussac:

P / T = constant => P1 / T1 = P2 / T2

=> P2 = T2 * P1 / T1

And remember you have to use absolute scale of temperature.

T1 = 25 + 273.15 = 298.15 K

T2 = 475 + 273.15 = 748.15 K

=> P2 = 748.15 K * 1.8 atm / 298.15 K = 4.5 atm

Answer: 4.5 atm
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3 years ago
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