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Igoryamba
2 years ago
10

A hydrate is a compound that has water molecules within its crystal structure. Magnesium sulfate heptahydrate, MgSO4·7H2O, is a

hydrated form of magnesium sulfate. The hydrated compound has 7 moles of H2O for each mole of MgSO4. When 5.06 grams of MgSO4·7H2O are heated to at least 300.oC in a crucible by using a laboratory burner, the water molecules are released. The sample was heated repeatedly, until the remaining MgSO4 had a constant mass of 2.47 grams. During this laboratory activity, appropriate safety equipment was used and safety procedures were followed.Explain why the sample in the crucible was heated repeatedly until the sample had a constant mass.
Chemistry
1 answer:
Alenkasestr [34]2 years ago
4 0

Answer:

We are heating the sample repeatedly to become a pure compound of only MgSO4 (withot H2O) and a constant mass.

Explanation:

Step 1: Data given

Mass of MgSO4·7H2O = 5.06 grams

The remaining MgSO4 had a constant mass of 2.47 grams.

Step 2: Explain why the sample in the crucible was heated repeatedly until the sample had a constant mass.

Before heating the compound has magnesium sulfate and water.

The total mass of this compound is 5.06 grams

By heating we try to eliminate the water.

After heating there remain mgSO4 with a mass of 2.47 grams

This means 5.06 - 2.47 = 2.59 grams is water. All of this is eliminated.

The heating process happens repeatedly to make sure the final compound is pure. So the 2.47 grams os only MgSO4. If the mass would not be constant. It means the compound is not pure, the not all the water is eliminated yet.

So we are heating the sample repeatedly to become a pure compound of only MgSO4 (withot H2O) and a constant mass.

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150 mL of 0.25 mol/L magnesium chloride solution and 150 mL of 0.35 mol/L silver nitrate solution are mixed together. After reac
Murljashka [212]

Answer:

0.175\; \rm mol \cdot L^{-1}.

Explanation:

Magnesium chloride and silver nitrate reacts at a 2:1 ratio:

\rm MgCl_2\, (aq) + 2\, AgNO_3\, (aq) \to Mg(NO_3)_2 \, (aq) + 2\, AgCl\, (s).

In reality, the nitrate ion from silver nitrate did not take part in this reaction at all. Consider the ionic equation for this very reaction:

\begin{aligned}& \rm Mg^{2+} + 2\, Cl^{-} + 2\, Ag^{+} + 2\, {NO_3}^{-} \\&\to  \rm Mg^{2+} + 2\, {NO_3}^{-} + 2\, AgCl\, (s)\end{aligned}.

The precipitate silver chloride \rm AgCl is insoluble in water and barely ionizes. Hence, \rm AgCl\! isn't rewritten as ions.

Net ionic equation:

\begin{aligned}& \rm Ag^{+} + Cl^{-} \to AgCl\, (s)\end{aligned}.

Calculate the initial quantity of nitrate ions in the mixture.

\begin{aligned}n(\text{initial}) &= c(\text{initial}) \cdot V(\text{initial}) \\ &= 0.25\; \rm mol \cdot L^{-1} \times 0.150\; \rm L \\ &= 0.0375\; \rm mol \end{aligned}.

Since nitrate ions \rm {NO_3}^{-} do not take part in any reaction in this mixture, the quantity of this ion would stay the same.

n(\text{final}) = n(\text{initial}) = 0.0375\; \rm mol.

However, the volume of the new solution is twice that of the original nitrate solution. Hence, the concentration of nitrate ions in the new solution would be (1/2) of the concentration in the original solution.

\begin{aligned} c(\text{final}) &= \frac{n(\text{final})}{V(\text{final})} \\ &= \frac{0.0375\; \rm mol}{0.300\; \rm L} = 0.175\; \rm mol \cdot L^{-1}\end{aligned}.

6 0
3 years ago
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Answer:

<h3>\huge{ \underline{ \underline { \bold{ \sf{ \orange{See \: below}}}}}}</h3>

Explanation:

▪️\underline{ \bold{ \sf{ \blue{Chemical \: reaction}}}}

⇒The composition , decomposition or displacement of molecules of matter during chemical change is called chemical reaction.

▪️\underline{ \bold{ \sf{ \purple{ \: Further \: more \: explanation}}}}

Various conditions bring about these changes. The chemical reactions are represented by chemicalequation. The compounds or elements that take part in chemical reaction are called reactant. They are written at the left side of an arrow that represent a change while the compound or elements that formed after the chemical change are called product. They are written at the right side of the arrow.

▪️\underline{ \bold{ \sf{ \purple{For \: example}}}}

When nitrogen reacts with hydrogen to form ammonia :

Nitrogen + Hydrogen ⇒ Ammonia

N₂ + 3H₂ ⇒ 2NH₃

<u>Presentation </u><u>of </u><u>a </u><u>chemical </u><u>reaction </u><u>in </u><u>the </u><u>form </u><u>of </u><u>equation </u><u>is </u><u>called </u><u>chemical </u><u>equation </u>. <u>Chemical equation may be word equations or formula equations.</u>

Hope I helped!

Best regards!!

3 0
2 years ago
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Explanation:

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