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kenny6666 [7]
4 years ago
15

I really need help :( can someone please help me T_T

Mathematics
1 answer:
Solnce55 [7]4 years ago
3 0

Answer: $25.41

Convert the percentage into a decimal, and then multiply that decimal by the total price to find the tip. Subtract the tip amount from the total price to find the price before the tip.

15 ÷ 100 = 0.15

15% of 29.90 = 0.15 · 29.90 = 4.48500 ≅ $4.49

$29.90 - $4.49 = $25.41

∴ the price before tip, <em>b</em>, of Mr. Johnson's lunch is $25.41.

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Someone help solve 6 &amp; 7 (will give brainliest)
riadik2000 [5.3K]
6.
T(I(h))= \sqrt{5000( \frac{12h-h^2}{36} )}
 
Since, function I stated that hours, h, pertains to the hours after 6am, and the question asks what is the temperature by 2pm, we will have h=8 because 2pm is 8 hours after 6am.

So,T(I(h))= \sqrt{5000( \frac{12(8)-(8)^2}{36} )}&#10;&#10;T(I(h))= \sqrt{5000( \frac{96-64}{36} )}&#10;&#10;T(I(h))= \sqrt{5000( \frac{32}{36} )}&#10;&#10;T(I(h))= \sqrt{ \frac{40000}{9} }&#10;&#10;T(I(h))=66.6666 or 67

so the answer is (3), 67.
6 0
3 years ago
Normal or natural variations in the quality of production output that are due purely to chance are _____.
nydimaria [60]

Normal or natural variations in the quality of production output that are due purely to chance are common causes.

According to the statement

we have to tell about the that cause which effect the quality and production output in the normal and natural variation.

So, For this purpose, we know that the

Common cause variation is present when the control chart of a process measure shows a random pattern of variation with all points within the control limits. When a control chart shows common cause variation, a process measure is said to be in statistical control or stable.

And due to this cause there is a lot of effect on the natural variations in the quality of production output.

So, Normal or natural variations in the quality of production output that are due purely to chance are common causes.

Learn more about common cause variation here

brainly.com/question/28040185

#SPJ4

6 0
2 years ago
how much money will you have in 10 years if you invest $12,000 at a 3.3% annual rate of interest compounded quarterly?
Andrej [43]

Answer:

The amount is $16718.7 and the interest is $4718.7.

Step-by-step explanation:

STEP 1: To find amount we use formula:

A=P(1+rn)n⋅t

A = total amount

P = principal or amount of money deposited,

r = annual interest rate

n = number of times compounded per year

t = time in years

In this example we have

P=$12000 , r=3.33% , n=4 and t=10 years

After plugging the given information we have

AAAA=12000(1+0.03334)4⋅10=12000⋅1.00832540=12000⋅1.393225=16718.7

STEP 2: To find interest we use formula A=P+I, since A=16718.7 and P = 12000 we have:

A16718.7II=P+I=12000+I=16718.7−12000=4718.7

4 0
4 years ago
8 hours and 12 minutes plus 3 hours in 15 minutes
nikklg [1K]
11 hours and 27 minutes
7 0
4 years ago
Read 2 more answers
Is 42(x + 14y) equivalent to 42x - 56y
g100num [7]

Answer:

No its not

Step-by-step explanation:

When 42(x + 14y) is simplified:

42(x + 14y)

Expand and remove the brackets. Remember brackets mean to multiply.

42*x

42x

42*14y

588y

42x+588y

Therefore 42x-56 is NOT EQUIVALENT to 42(x + 14y) but is equivalent to 42+588y

3 0
4 years ago
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