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4 years ago

Is it possible to solve a quadratic equation that is not factorable over the set of integers? Explain.

Mathematics

1 answer:

zvonat [6]4 years ago

8 0

Answer:

Yes

Step-by-step explanation:

Yes it is possible to solve a quadratic equation that is not factorable over the set of integers.

The solution may vary like Integers, rationals, irrationals or complex solutions.

To find two roots of the equation we can always use the formula given below to solve a quadratic equation,

For the quadratic equation,

$ax^2+bx+c=0$ , we have,

$x= \frac{-b\pm \sqrt{b^2-4 ac}}{2a}$

If the discriminant is greater than $b^2$ , we get complex roots.

You might be interested in

The sum of two rational numbers is 4/7.If one of them is 3/14 find another numbers.

VMariaS [17]

Answer:

5/14

Step-by-step explanation:

let the aaded no be x

3/14 + x = 4/7

x = 4/7-(3/14)

x = 5/14

here added no is 5/14

4 0

4 years ago

A triangular plot of land has side lengths of 2,000 feet, 2,100 feet and 2,900 feet. Does the plot of land form a right triangle

Bingel [31]

The plot of land forms right triangle.

Step-by-step explanation:

Let,

the three sides are a,b and c.

The sum of square of two sides equals to the square of third side. We will consider the larger side as c, therefore,

a= 2000 feet

b= 2100 feet

c= 2900 feet

Using Pythagoras theorem;

$a^2+b^2=c^2\\(2000)^2+(2100)^2=(2900)^2\\4000000 + 4410000 = 8410000\\8410000 feet = 8410000 feet$

As the three sides satisfy pythagoras theorem, therefore, the plot of land form right triangle.

The plot of land forms right triangle.

Keywords: triangle, pythagoras theorem

Learn more about pythagoras theorem at:

#LearnwithBrainly

3 0

4 years ago

(3a^3-5b^3)+blank a^3+blank b^3=(a^3+b^3)

lions [1.4K]

Answer:

(3a³-5b³)+ (-2)a³ +6b³=(a³+b³)

Step-by-step explanation:

First, lets remove the brackets. There is no "-" before the brackets, so we can just remove them at all.

3a³-5b³+ ...a³ +...b³=a³+b³

Now we can joint similar monoms (with variable a) ( and with variable b) in the left side of equation

3a³+...a³ -5b³ +...b³=a³+b³

Now we can notice that 3a³+...a³=a³ (1) and

-5b³ +...b³=b³ (2)

Lets find deduct 3a³ from both sides of (1)

...a³= a³-3a³

...a³= -2a³ So instead ... we have to type -2 (-2 is negative sowe type -2 in brackets).

Similarly lets add 5b³ to both sides of (2)

-5b³ +...b³=b³

-5b³ +5b³ +...b³=b³+5b³

...b³=6b³ So instead ... we have to type 6.

6 0

3 years ago

Graph y = −x2 − 2. Identify the vertex of the graph. Tell whether it is a minimum or maximum.

Kitty [74]

Y = - x^2 - 2

the vertex of - x^2 will be at (0,0)
the -2 translates the graph down 2 units

The answer is the vertex is at (0,-2) and as the coefficient of x^2 is negative it is a maximum

Answer is D.

8 0

3 years ago

Read 2 more answers

Someone please help me!!

Rom4ik [11]

Answer:

-1/2 is the answer i think

3 0

3 years ago