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Troyanec [42]
3 years ago
12

Write down the 1st term in the sequence given by: T(n) = n² + 3

Mathematics
1 answer:
Nadya [2.5K]3 years ago
4 0

Answer:

4

Step-by-step explanation:

T(n) = n² + 3

T(1) = 1² + 3 = 1 + 3 = 4

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PLEASE HELP MEEEEEEEEEEEEEEEEEEE
pickupchik [31]

This sequence be represented as a recursive equation by a1=8 and an=2a1

<u>Step-by-step explanation</u>:

  • 'Recursive' refers to the repetition of a specific process in a sequence.
  • The given sequence is {8,16,32,64}.
  • If the value is 2 times the previous value, then an=2a(n-1)

Let a1=8,

then a2 = 2a(2-1)

⇒ a2 = 2a1

⇒ a2 = 2(8)

⇒ a2 = 16

Similarly,

For a2=16,

⇒ a3 = 2(a2)

⇒ a3 = 2(16)

⇒ a3 = 32

For a3=32,

⇒ a4 = 2(a3)

⇒ a4 = 2(32)

⇒ a4 = 64

∴ The equation is recursive as a1=8 and an=2a1 to follow the sequence.

8 0
3 years ago
In the equation, 1/4n+5=51/2 what is n equal to?
BlackZzzverrR [31]

Answer:

N = 2

Step-by-step explanation:

5 1/2 - 5

= 1/2

1/2 divided by 1/4 = 2

N = 2

5 0
3 years ago
Read 2 more answers
What is an equation of the line that passes through the point (-2,7) and is perpendicular to the line x-6y=42 ?
Natali5045456 [20]

Answer:

The equation of the line that passes through the point (-2,7) and is perpendicular to the line x-6y=42 is

6x+y=-5

Step-by-step explanation:

Given:  

Let,  

point A( x₁ , y₁) ≡ ( -2 , 7)

To Find:  

Equation of Line  that passes through the point (-2,7) and is perpendicular to the line x-6y=42=?  

Solution:  

x-6y=42    ..................Given

which can be written as

y=mx+c

Where m is the slope of the line

∴ y=\dfrac{x}{6}-7

On Comparing we get

Slope = m = \dfrac{1}{6}

The Required line is Perpendicular to the above line.

So,

Product of slopes = - 1

m\times m_{1}=-1\\Substituting\ m\\ \dfrac{1}{6} m_{1}=-1\\\\m_{1}=-6

Slope of the required line is -6

Equation of a line passing through a points A( x₁ , y₁) and having slope m is given by the formula,  

i.e equation in point - slope form

(y-y_{1})=m(x-x_{1})

Now on substituting the slope and point A( x₁ , y₁) ≡ ( -2, 7) and slope = -6 we get

(y-7)=-6(x--2)=-6(x+2)=-6x-12\\\\\therefore 6x+y=-5.......is\ the required\ equation\ of\ the\ line

The equation of the line that passes through the point (-2,7) and is perpendicular to the line x-6y=42 is

6x+y=-5

3 0
3 years ago
Need help with this problem, please. The sum of three numbers is -3. The last number is three times the first. The last number i
oee [108]

Answer:

The three numbers are -1 6/7, -5 4/7, and 5 3/7

Step-by-step explanation:

The three numbers can be represented as...

x, 3x+11, and 3x

x+3x+3x+11=-2

7x+11=-2

7x=-13

x= - 1 6/7

3x= -5 4/7

3x+11= 5 3/7

4 0
3 years ago
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Four oranges cost a total of 90 cents. At this rate, what is the cost of 3 dozen oranges? Step by step will put brilliants
allsm [11]
Four oranges cost 90 cents, an orange costs 90/4 cents, which is around 22.5 cents. Multiply this by 36 to get the cost of 3 dozen oranges, so 22.5 times 36 is 810, 810 cents, or 8.10 dollars.
8 0
3 years ago
Read 2 more answers
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