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aliina [53]
3 years ago
7

D%20%29" id="TexFormula1" title="f(x) = (x - \frac{2}{9} )(x + \frac{1}{2} )" alt="f(x) = (x - \frac{2}{9} )(x + \frac{1}{2} )" align="absmiddle" class="latex-formula">
FIND THE ZEROS OF THE FUNCTION
Mathematics
1 answer:
Aleonysh [2.5K]3 years ago
3 0
f(x) = (x -  \dfrac{2}{9} )(x +  \dfrac{1}{2} )

\text {When } f(x) = 0 :

(x -  \dfrac{2}{9} )(x +  \dfrac{1}{2} ) = 0

(x -  \dfrac{2}{9} ) = 0  \text { or }  (x +  \dfrac{1}{2} ) = 0

x =  \dfrac{2}{9}  \text { or } x =  -\dfrac{1}{2}

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Please come answer ASAP!!!<br> 5 - n divided by 3 = 4 what is the value of n?
Varvara68 [4.7K]

Hey there!

The equation we have been given is 5 - n/3 = -4.

Let's start by subtracting 5 from each side.

-n/3 = -9

Multiply each side by 3.

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Multiply each side by -1.

n = 27

Check our answer.

5 - 27/3 = -4

5 - 9 = -4

-4 = -4

The value of n is 27.

Hope this helps!

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