<img src="https://tex.z-dn.net/?f=f%28x%29%20%3D%20%28x%20-%20%20%5Cfrac%7B2%7D%7B9%7D%20%29%28x%20%2B%20%20%5Cfrac%7B1%7D%7B2%7

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3 years ago

D%20%29" id="TexFormula1" title="f(x) = (x - \frac{2}{9} )(x + \frac{1}{2} )" alt="f(x) = (x - \frac{2}{9} )(x + \frac{1}{2} )" align="absmiddle" class="latex-formula">
FIND THE ZEROS OF THE FUNCTION

Mathematics

1 answer:

Aleonysh [2.5K]3 years ago

3 0

$f(x) = (x - \dfrac{2}{9} )(x + \dfrac{1}{2} )$

$\text {When } f(x) = 0 :$

$(x - \dfrac{2}{9} )(x + \dfrac{1}{2} ) = 0$

$(x - \dfrac{2}{9} ) = 0 \text { or } (x + \dfrac{1}{2} ) = 0$

$x = \dfrac{2}{9} \text { or } x = -\dfrac{1}{2}$

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3 years ago

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Galina-37 [17]

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Step-by-step explanation:

We have the following data given:

130, 135, 140, 120, 130, 130, 144, 143, 140, 130, 150

If we sort the values on increasing order we got:

120 130 130 130 130 135 140 140 143 144 150

The minimum and maximum are:

$Min =120, Max= 150$

The first quartile can be calculated with this data:

130, 135, 140, 120, 130, 130

And the middle value is:

$Q_1 = \frac{140+120}{2}=130$

The median is the value in the 6th position from the dataset ordered and we got:

$Median= 135$

The third quartile can be calculated with this data:

135 140 140 143 144 150

And the middle value is:

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The five number summary for this case:

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8 0

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qwelly [4]

Answer:

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3 years ago