Answer
f(t)=2cos(t)
Step-by-step explanation:
let's describe the situation first, a fly is starting 2 meters from the bulb and flies towards the bulb and when it is really close to the bulb, it flies 2 meters further away from the bulb this means that it reaches d = 0m (distance from the bulb) and then flies further 2 meters so d = -2m.
it this point the fly returns back and touches the bulb and flies away (ends it's oscillatory motion ). d = 0 again and story ends here.
here if we want to model this problem with time function , the cosine function seems the best fit with amplitude of 2, so the answer is f(t) = 2cos(t).
Now you can ask why cosine function? well if you look at the graph or the plot of the function it perfectly captures the physical situation going on here in this problem.
Domain is 0 to 2
because it is one complete cycle and the range is -2 to +2.
bearing in mind that there are 60 minutes in 1 degree, and 60 seconds in 1 minute.
60°19'39"
so 39 seconds is really 39/60 minutes, or 0.65 minutes
so 19'39" is really 19.65'.
since there are 60 minutes in 1 degree, then 19.65' is really 19.65/60 degrees, or 0.3275°.
60°19'39" is then 60.3275°.
Answer: The range of the medians of the numbers left and right of the median of the entire data set.
Answer:
(1/2, -1/2)
Step-by-step explanation:
To find a midpoint add the two x's and divide by 2 so -1+2 / 2 = 1/2
add the two y's and divide by 2 so 4-5 / 2 = -1/2
Put the two numbers together as a coordinate (1/2, -1/2)
Answer:
Step-by-step explanation:
The numbers are 11 & 12
Explanation:
Let the first number be f and the second |number be s
Now the square of first No. is 23 less than the square of second No.
ie. f
2
+
23
=
s
2
. . . . . (1)
The second No. is 1 more than the first
ie f
+
1
=
s . . . . . . . . . . .(2)
squaring (2), we get
(
f
+
1
)
2
=
s
2
expanding
f
2
+
2
⋅
f
+
1
=
s
2 . . . . . (3)
Now (3) - (1) gives
2
⋅
f
−
22
=
0
or
2
⋅
f
=
22
thus, f
=
22
2
=
11
and s
=
f
+
1
=
11
+
1
=
12
So the numbers are 11 & 12
