Find 2 solutions of the equation y=3x-5

2 answers:

5 0

(1,-2)
(2,1)
Pick any number and plug it in as x. Ex: 4.
So the equation will now be y=3(4)-5
Next do 3 times 4 which equals 12.
After that do 12-5 which equals 7.
After you do that the equation will look like: y=7
Now take the x and y values and put it as a point: (4,7)

larisa [96]3 years ago

4 0

-- point (1, -2)

-- point (10, 25)

You might be interested in

Which of the following fractions has the same value as the decimal number 0.65?

boyakko [2]

Answer:

13/20

Step-by-step explanation:

To find this, divide 13 by 20 to get .65

Hope this helped!

4 0

3 years ago

Store A: $25 for a 45 minute lesson Store B: $30 for a 1 hour lesson Store C: $45 for a 1.5 hour lesson Store D: $80 for three 1

Vikentia [17]

Answer: Store C by far, less money more time.

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

What is the slope of the line that passes through the points (-10, -8) and

bazaltina [42]

First of all we have to find the slope

m = y₂-y₁ / x₂-x₁

m = -8 + 16 / -10 + 8

m = 8/-2

m = -4

y-y₁ = m (x-x₁)

y + 8 = -4 (x + 10)

y + 8 = -4x - 40

y = -4x -40 - 8

y = -4x -48

7 0

2 years ago

A bag of trail mix weighs 2 lb. By weight, 20% of the bag is oats. How many pounds is the oats portion of the trail mix? (a) Wri

posledela

Answer: 0.4 pounds of the trail mix is oats.

To find the answer, you can set up a proportion. We can use the percent proportion below.

part/whole = percent/100

x/2 = 20/100

To solve this you cross multiply and divide.

100x = 40
x = 0.4

3 0

3 years ago

I need help with both of them please!( Sample questions 13 and 14)

zaharov [31]

$First~exercise! \\ We~ have `there ~some~ triangles.(2) \\ 1)~In~ a ~triangle~,the~degree~of~all~angles~is~180! \\ We~have~2~angles~known,so: \\ 180=x+45+56 \\ 180=101+x \\ x=79 \\ \\ Second~triangle! \\ We~have~to~find~2~angles! \\ An ~elongated`~angle~have~180~degrees! \\ 180=79+50+y \\ y=51. \\ In~the~second~triangle~,we~have~to~find~the`third~angle. \\ We~have~a~right~angle,so--\ \textgreater \ 90~degrees! \\ 180=90+51+z \\ z=39! \\ We~found~all~the~angles!(We~are`happy~now!!!~:))) \\ Second~exercise! \\ With~the~Pythagoras' Theorem,we~can~find~the~diagonal~in~this~ \\ rectangle! \\ c ^{2} =10 ^{2} +14 ^{2} \\ c ^{2} =100+196 \\ c= \sqrt{296} \\ c=17,20...$

8 0

3 years ago