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Anna007 [38]
3 years ago
10

Find 2 solutions of the equation y=3x-5

Mathematics
2 answers:
SpyIntel [72]3 years ago
5 0
(1,-2)
(2,1)
Pick any number and plug it in as x. Ex: 4.
So the equation will now be y=3(4)-5
Next do 3 times 4 which equals 12.
After that do 12-5 which equals 7. 
After you do that the equation will look like: y=7
Now take the x and y values and put it as a point: (4,7)
larisa [96]3 years ago
4 0
-- point  (1, -2)

-- point  (10, 25)
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Answer:

Answer is option b)

<em>Answer is </em><em>given below with explanations</em><em>. </em>

Step-by-step explanation:

a \: walking \: path \: is \: represented \: by \:  \\ y =  - 4x - 6 \\ 4x + y + 6 = 0 \\ given \: that \\ a \: new \: path \: will \: be \: built \: perpendicular  \\ \: to \:  \: the \: walking \: path \\ the \: equation \: of \: the \: line \: perpendicular \: to \\ 4x + y + 6 = 0 \: is \\ x - 4y + k = 0 \\ since \: it \: passes \: through \: ( - 4,10) \\ substitute \: x \:  =  - 4\: and \: y = 10 \: in \: required \: equation \\  - 4 - 4(10) + k = 0 \\ k = 44 \\ then \: the \: equation \: is \\ x - 4y + 44 = 0 \\ adding \: 4y \: on \: both \: sides \\ x + 44 = 4y \\ dividing \: by \: 4 \: on \: both \: sides \\ y =  \frac{x}{4}  + 11 \\ y =  \frac{1}{4} x + 11 \\ so \: the \: answer \: is \: option \: b) \:   \frac{1}{4} x + 11

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<em>THANKS FOR GIVING ME THE OPPORTUNITY</em><em> </em><em>TO ANSWER YOUR QUESTION</em><em>. </em>

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ElenaW [278]

Answer:

n(S\cap F \cap R)=7

Step-by-step explanation:

The Universal Set, n(U)=2092

n(S)=1232\\n(F)=879\\n(R)=114

n(S\cap R)=23\\n(S\cap F)=103\\n(F\cap R)=14

Let the number who take all three subjects, n(S\cap F \cap R)=x

Note that in the Venn Diagram, we have subtracted n(S\cap F \cap R)=x from each of the intersection of two sets.

The next step is to determine the number of students who study only each of the courses.

n(S\:only)=1232-[103-x+x+23-x]=1106+x\\n(F\: only)=879-[103-x+x+14-x]=762+x\\n(R\:only)=114-[23-x+x+14-x]=77+x

These values are substituted in the second Venn diagram

Adding up all the values

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The number of students who have taken courses in all three subjects, n(S\cap F \cap R)=7

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