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3 years ago

a model house has a scale of 1 in :2 ft. if the real house is 26 ft wide then how wide is the model house

Mathematics

2 answers:

MArishka [77]3 years ago

7 0

Divide the width by 2, as that is your scale.
26 / 2 = 13
The house would be 13 inches long.

Dominik [7]3 years ago

3 0

Divide the wide of the house by two and times it at one inch. 26/2=13*1=13 inches

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Which theorem shows how the triangles are similar:

yan [13]

Answer:

AA similarly is correct....

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3 years ago

The vertex of the parabola below is at the point (2, 4), and the point (3, 6) is on the parabola. What is the equation of the pa

Liula [17]

<span>C and B are *candidates* for being the correct solution
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2 years ago

Choose the correct simplification of the expression (-9a^3b^2c^10)^0

Flauer [41]

Option C: 1 is the simplification of the expression $\left(-9 a^{3} b^{2} c^{10}\right)^{0}$

Explanation:

The given expression is $\left(-9 a^{3} b^{2} c^{10}\right)^{0}$

We need to simplify the given expression.

<u>Simplification:</u>

To simplify the given expression, let us apply the exponent rule, $a^{0}=1$ where $a \neq 0$

Thus, the the exponent rule $a^{0}=1$ means that any value (except zero) to the power of zero is equal to one.

Thus, the expression $\left(-9 a^{3} b^{2} c^{10}\right)^{0}$ becomes,

$\left(-9 a^{3} b^{2} c^{10}\right)^{0}=1$

Therefore, the simplified expression is 1

Hence, Option C is the correct answer.

8 0

2 years ago

The figure below shows part of a stained-glass window depicting the rising sun. Which function can be used to find the area of t

Kryger [21]

Answer:

$A(w) = w^2 + 5w - \frac{1}{8}\pi w^2$

Step-by-step explanation:

A = the area of the region outside the semicircle but inside the rectangle

w = the width of the rectangle or diameter of the semicircle

Since "A" is determined by "w", therefore, "A" is a function of "w" = A(w).

A(w) = (area of rectangle) - (area of semicircle)

$A(w) = (l*w) - (\frac{1}{2} \pi r^2)$

Where,

lenght of rectangle (l) = w + 5

width of rectangle (w) = w

r = ½*w = $\frac{w}{2}$

Plug in the values:

$A(w) = ((w + 5)*w) - (\frac{1}{2} \pi (\frac{w}{2})^2)$

Simplify

$A(w) = (w^2 + 5w) - (\frac{1}{2} \pi (\frac{w^2}{4})$

$A(w) = w^2 + 5w - \frac{1}{2}*\pi*\frac{w^2}{4}* \pi$

$A(w) = w^2 + 5w - \frac{1*\pi*w^2}{2*4}$

$A(w) = w^2 + 5w - \frac{1*\pi w^2}{8}$

$A(w) = w^2 + 5w - \frac{1}{8}\pi w^2$

3 0

3 years ago

How many kilograms are there in one tonne

faust18 [17]

1000 kilograms

Hope this helps

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2 years ago