Since the graph of the given functions is a straight line, the graph belongs to a linear function, as all linear functions have their graphs as a straight line. For a non-linear function the graph is not a straight line.
For a relation (non-function), the line passes through same value of x for more than one points.
Hence the correct answer is "Linear Function"
Area=pi times radiius^2
radius=diameter/2
diamter=5
radius=5/2=2.5
pi=3.14 aprox
area=3.14 times 2.5^2
area=3.14 times 6.25
area=19.625 ft^2
round
19.6 round up
20
the answer is 20 ft^2
Answer:
6 containers
6 ounces of fruit snack will be left over
Step-by-step explanation:
1 pound = 16 ounces
⇒ ¹/₂ pound = 8 ounces
Total weight = weight of dried apples + weight of dried cranberries
= 36 + 18
= 54 ounces
Containers needed = total weight ÷ weight of snacks in one container
= 54 ÷ 8
= 6.75
Therefore, he will fill 6 containers
Snack left over = total weight - (number of containers × weight of snacks one container will hold)
= 54 - (6 × 8)
= 54 - 48
= 6 ounces
Let x be the number of pastries they must sell.
$3.50x≥140
This inequality states that for the number of pastries at 3.50 dollars each must be greater than or equal to 140. Solve for x.
Complete question :
It is estimated 28% of all adults in United States invest in stocks and that 85% of U.S. adults have investments in fixed income instruments (savings accounts, bonds, etc.). It is also estimated that 26% of U.S. adults have investments in both stocks and fixed income instruments. (a) What is the probability that a randomly chosen stock investor also invests in fixed income instruments? Round your answer to decimal places. (b) What is the probability that a randomly chosen U.S. adult invests in stocks, given that s/he invests in fixed income instruments?
Answer:
0.929 ; 0.306
Step-by-step explanation:
Using the information:
P(stock) = P(s) = 28% = 0.28
P(fixed income) = P(f) = 0.85
P(stock and fixed income) = p(SnF) = 26%
a) What is the probability that a randomly chosen stock investor also invests in fixed income instruments? Round your answer to decimal places.
P(F|S) = p(FnS) / p(s)
= 0.26 / 0.28
= 0.9285
= 0.929
(b) What is the probability that a randomly chosen U.S. adult invests in stocks, given that s/he invests in fixed income instruments?
P(s|f) = p(SnF) / p(f)
P(S|F) = 0.26 / 0.85 = 0.3058823
P(S¦F) = 0.306 (to 3 decimal places)
