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zaharov [31]
3 years ago
8

At age 25, to save for retirement, you decide to deposit $75 at the end of each month in an ira that pays 6.5% compounded monthl

y. how much will you have from the ira when you retire at age 65? find the interest.
Mathematics
1 answer:
Alex787 [66]3 years ago
4 0
Let P= $75, r=0.0054166, n= 40. In the future worth formula, F= P((1+r)^(n-1) -1) / r, it would yield a future worth of 3,247.16 at the age of 65. And the interest rate is I= (r^n-10)/(r-1). It yields an interest of 1.033
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Answer:

\frac{(17)(0.038)^2}{32.64} \leq \sigma^2 \leq \frac{(17)(0.038)^2}{6.66}

0.0008 \leq \sigma^2 \leq 0.0037

Step-by-step explanation:

Data given and notation

s=0.038 represent the sample standard deviation

\bar x represent the sample mean

n=18 the sample size

Confidence=97.5% or 0.975

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population mean or variance lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.

The Chi Square distribution is the distribution of the sum of squared standard normal deviates .

Calculating the confidence interval

The confidence interval for the population variance is given by the following formula:

\frac{(n-1)s^2}{\chi^2_{\alpha/2}} \leq \sigma^2 \leq \frac{(n-1)s^2}{\chi^2_{1-\alpha/2}}

The next step would be calculate the critical values. First we need to calculate the degrees of freedom given by:

df=n-1=18-1=17

Since the Confidence is 0.975 or 97.5%, the value of \alpha=0.025 and \alpha/2 =0.0125, and we can use excel, a calculator or a table to find the critical values.  

The excel commands would be: "=CHISQ.INV(0.0125,17)" "=CHISQ.INV(0.9875,17)". so for this case the critical values are:

\chi^2_{\alpha/2}=32.64

\chi^2_{1- \alpha/2}=6.66

And replacing into the formula for the interval we got:

\frac{(17)(0.038)^2}{32.64} \leq \sigma^2 \leq \frac{(17)(0.038)^2}{6.66}

0.0008 \leq \sigma^2 \leq 0.0037

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