I found it quicker than i thought i would! the positive x-intercept is (4,0). negative x intercept is (-
![\frac{1}{3}](https://tex.z-dn.net/?f=%20%5Cfrac%7B1%7D%7B3%7D%20)
,0)
Answer: 30
Step-by-step explanation:
3+4+3=10 400/10=40 so each has 40 so math has 120 120*25=3000 for physics is 4*40 so 160 160*20=3200 9800-3000-3200=3600 3*40=120 3600/120=30
10
Workings out
(2/5)*25=10
Answer:
A. 14x14x28
B. The maximum volume is 5488 cuibic inches
Step-by-step explanation:
The problem states that the box has square ends, so you can express volume with:
![v=x^{2} y](https://tex.z-dn.net/?f=v%3Dx%5E%7B2%7D%20y)
Using the restriction stated in the problem to get another equation you can substitute in the one above:
![4x+y=84\\\\](https://tex.z-dn.net/?f=4x%2By%3D84%5C%5C%5C%5C)
Substituting <em>y</em> whit this equation gives:
![v=x^{2} (84-4x)\\\\v=84x^{2} -4x^{3}](https://tex.z-dn.net/?f=v%3Dx%5E%7B2%7D%20%2884-4x%29%5C%5C%5C%5Cv%3D84x%5E%7B2%7D%20-4x%5E%7B3%7D)
Now find the limit of <em>x</em>:
![\frac{84x^{2}-4x^{3}}{dx}=168x-12x^{2}\\\\x=\frac{168}{12}=14](https://tex.z-dn.net/?f=%5Cfrac%7B84x%5E%7B2%7D-4x%5E%7B3%7D%7D%7Bdx%7D%3D168x-12x%5E%7B2%7D%5C%5C%5C%5Cx%3D%5Cfrac%7B168%7D%7B12%7D%3D14)
Find the length:
![y=84-4(14)=28](https://tex.z-dn.net/?f=y%3D84-4%2814%29%3D28)
You can now calculate the maximum volume:
![v=(14)^{2}(28)= 5488](https://tex.z-dn.net/?f=v%3D%2814%29%5E%7B2%7D%2828%29%3D%205488)