Answer:
48
Step-by-step explanation:
You can do it with cross multiplication
Answer:
Mean of sampling distribution = 5.10 alcoholic drinks per week
Standard deviation of the sampling distribution = 0.11
Step-by-step explanation:
We are given the following in the question:
Mean, μ = 5.10 alcoholic drinks per week
Standard Deviation, σ = 1.3401
Sample size, n = 150
a) Mean of sampling distribution
The best approximator for the mean of the sampling distribution is the population mean itself.
Thus, we can write:

b) Standard deviation of the sampling distribution

<span> value
Weighted mean average = ---------------------------
number of brands
value = mean price of computers from Store
#1 * number of brands from store #1 + mean price of computers from store #2 * number of brands from store #2
value = $799.99 * 2 + $679.99 * 4 = $4,319.94
number of brands = 2 + 4 = 6
weighted average = $4,319.94 / 6 = $ 719.99
Answer: option b. $719.99
</span>
Answer:
<h3>The value C(t) of the car after 5 years is $12709.</h3>
Step-by-step explanation:
Given that Landon bought a new car for $16,000 and it depreciates 4.5% every year.
<h3>To find the value C(t) of the car after 5 years:</h3>
Initial value 
Depreciation rate is 
<h3>∴ r=0.045</h3>
Period , t=5 years

Substitute the values we get



∴ 
<h3>The value C(t) of the car after 5 years is $
12709</h3>