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3 years ago

I don't understand what to do because I don't understand the question

Mathematics

1 answer:

kirill [66]3 years ago

4 0

Find the 2 different rates at which the farm worker worked:

3 pints
--------- = 0.75 pint/min
4 min

2 pints
---------- = 0.67 pint/ min
3 min

Then you need to subtract 0.67 pint/min from 0.75 pint/min to answer this question.

Alternatively, subtract 2/3 pint/min from 3/4 pint/min.

You might be interested in

The pay, P, at a certain job is calculated by the formula P=Bh, where b is the base pay and h is the number of hours worked. if

Alexxx [7]

If you would like to know the Tom's pay for the week, you can calculate this using the following steps:

P = B * h
P ... the pay
B ... the base pay
h ... the number of hours worked

B = $6.35
h = 28 hours
P = B * h = $6.35 * 28 hours = $177.8

<span>Tom's pay for the week would be $177.8.</span>

5 0

3 years ago

Can you please help???

marusya05 [52]

Answer:

2 or 3 I think

I gessssssssssing

5 0

2 years ago

Can someone help me pls ?

r-ruslan [8.4K]

Answer:

58.3%

Step-by-step explanation:

Add up the numbers that are only in one circle

18+7+10 = 35

Take this over 60

35/60=.58333333

Change to percent form to one decimal place

58.3%

3 0

3 years ago

Find the value of the expression.<br> x + y + 5<br> for x = 3 and y = 4

Alexandra [31]

Answer:

Step-by-step explanation:

if x = 3

and y = 4

3 + 4 + 5 = 12

what grade is this

3 0

2 years ago

Can anyone help me about question 2

madreJ [45]

9514 1404 393

Answer:

3(4/3)^2543

Step-by-step explanation:

Using logarithms base 2, we have ...

$(a_n)^{\log{a_n}}=(a_{n+1})^{\log{a_{n-1}}}\\\\(\log{a_n})(\log{a_n}) = (\log{a_{n-1}})(\log{a_{n+1}}) \\\\ \dfrac{\log{a_{n+1}}}{\log{a_{n}}}=\dfrac{\log{a_n}}{\log{a_{n-1}}}=\dots\dfrac{\log_2{16}}{\log_2{8}}=\dfrac{4}{3}$

That is, the ratio of each term to the previous is a constant equal to 4/3. This is the definition of a geometric sequence. This sequence has first term 3 and common ratio 4/3, so the general term is ...

$\log_2 a_n=3\left(\dfrac{4}{3}\right)^{n-1}$

and the 2544th term is ...

$\boxed{\log_2{a_{2544}}=3\left(\dfrac{4}{3}\right)^{2543}}$

8 0

3 years ago