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3 years ago

Compare 51.5 hectograms to 51,500 decigrams. How do each of these values compare to a gram and which represents a larger mass?

2 answers:

8 0

These values when compared seem to be the same. They are equal. If we convert them to the same units, they results to the value which is:

51.5 Hectograms = 5100 Grams

51,500 Decigrams = 5100 Grams

Hope this answers the question. Have a nice day.

snow_lady [41]3 years ago

5 0

51.5 Hectograms + 5100 Grams
51,500 Decigrams = 5100 Grams

They have same mass because they equal each other.

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P=2L+2W find the width of a rectangle whose length is 35 and perimeter is 82in

mart [117]

Answer:

Step-by-step explanation:

We can fill in what we know which is the length and perimeter.

82=2(35)+2(w)

Multiply 35 x 2 = 70

82-70= 12

12/2=6

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3 years ago

How many times bigger is 3x10^8 then 6x10^7? Plz put an explanation

myrzilka [38]

Answer:

240000000 times bigger.

If we solve 3x10^8 we get 300000000

Then if we solve for 6x10^7 we get 60000000

Subtract those two using long subtraction to evaluate and we get 240000000

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2 years ago

Evaluate cube root of 5 multiplied by square root of 5 over cube root of 5 to the power of 5.

Andre45 [30]

Answer:

Option d) 5 to the power of negative 5 over 6 is correct.

$\dfrac{\sqrt[3]{\bf 5} \times \sqrt{\bf 5}}{\sqrt[3]{\bf 5^{\bf 5}}}= 5^{\frac{\bf -5}{\bf 6}}$

Above equation can be written as 5 to the power of negative 5 over 6.

ie, $5^\frac{\bf -5}{\bf 6}$

Step-by-step explanation:

Given that cube root of 5 multiplied by square root of 5 over cube root of 5 to the power of 5.

It can be written as below

$\dfrac{\sqrt[3]{5} \times \sqrt{5}}{\sqrt[3]{5^5}}$

$\dfrac{\sqrt[3]{5} \times \sqrt{5}}{\sqrt[3]{5^5}}= \dfrac{5^{\frac{1}{3}} \times 5^{\frac{1}{2}}}{5^{\frac{5}{3}}}$

$\dfrac{\sqrt[3]{5} \times \sqrt{5}}{\sqrt[3]{5^5}}= \dfrac{5^{\frac{1}{3}+\frac{1}{2}}}{5^{\frac{5}{3}}}$

$\dfrac{\sqrt[3]{5} \times \sqrt{5}}{\sqrt[3]{5^5}}= \dfrac{5^{\frac{2+3}{6}}}{5^{\frac{5}{3}}}$

$\dfrac{\sqrt[3]{5} \times \sqrt{5}}{\sqrt[3]{5^5}}= 5^{\frac{5}{6}} \times 5^{\frac{-5}{3}}$

$\dfrac{\sqrt[3]{5} \times \sqrt{5}}{\sqrt[3]{5^5}}= 5^{\frac{5-10}{6}}$

$\dfrac{\sqrt[3]{5} \times \sqrt{5}}{5^5}= 5^{\frac{-5}{6}}$

Above equation can be written as 5 to the power of negative 5 over 6.

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3 years ago

PLS HELP!!!!!!!!!!!!

seropon [69]

Answer:

72 55/76

Step-by-step explanation:

it's right trust me <3

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2 years ago

Read 2 more answers

Conducting numerous, separate statistical analyses increases the chance that one or more of the results appear to be statistical

Kobotan [32]

A family-wise inflation of error rate is the <u>increase</u> in the probability that one or more results of a numerous, independently (separately) conducted statistical analyses to become statistically significant, but these results can actually be attributed to random variation or measurement error.

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2 years ago