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3 years ago

Which position of the bar magnet would have the strongest attraction to the north pole of the other bar magnet

Mathematics

2 answers:

Thepotemich [5.8K]3 years ago

7 0

The middle is your answer

lawyer [7]3 years ago

5 0

The strength of the field varies depending on its location around the magnet. The magnetic field of a bar magnet is strongest at either pole of the magnet. It is equally strong at the north pole compared with the south pole.

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Which one is distributive property

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Step-by-step explanation:

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3 years ago

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What time is four and a half hour before 11:45 am

MrRa [10]

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Find the area of the circle [?] square units

xxMikexx [17]

Answer:

169π or 530.93

Step-by-step explanation:

The formula for the area of a circle is πr²

Here, the radius is given to be 13.

So, let's just plug it into the formula as r

π x 13²

π x 169

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3 years ago

Evaluate the function for the given value.

maks197457 [2]

Answer:

$g(t) = 2 \cdot 0.4t \ for \ t = -2\\g(-2) = 2 * 0.4*-2 = -1.6$

none of the above.

Are u sure question is correct?

7 0

3 years ago

Confirm that f and g are inverses by showing that f(g(x)) = x and g(f(x)) = x.

Molodets [167]

$f(x)= \frac{x-9}{x+5}$
$g(x)= \frac{-5x-9}{x-1}$
$f(g(x))= \frac{ \frac{-5x-9}{x-1} -9}{ \frac{-5x-9}{x-1}+5 }$
$f(g(x))= \frac{-5x-9-9(x-1)}{-5x-9+5(x-1)}$
$f(g(x))= \frac{-5x-9-9x+9}{-5x-9+5x-5}$
$f(g(x))= \frac{-14x}{-14}=x$
$g(f(x))= \frac{-5 \frac{x-9}{x+5}-9 }{ \frac{x-9}{x+5}-1 }$
$g(f(x))= \frac{-5x+45-9(x+5)}{x-9-1(x+5)}$
$g(f(x))= \frac{-5x+45-9x-45}{x-9-x-5}$
$g(f(x))= \frac{-14x}{-14}=x$

6 0

3 years ago