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defon
3 years ago
12

The temperature of the furnace is 1200 and cool at a rate of 15 per minute the temperature of another furnace is 900 and is heat

at a rate of 5 per minutes after how many minutes will the furnace be at the same temperature
Mathematics
1 answer:
Hunter-Best [27]3 years ago
6 0

Answer:

After 15 minutes, the temperature of both the furnaces will be same.

Step-by-step explanation:

Let x be the minutes when the temperature of both becomes same.

Now, as per question:

Temperature of the furnace after x minutes that is cooling at the rate of 15 degree per minute is given as:

T=1200-15x

Temperature of the furnace after x minutes that is heating at the rate of 5 degree per minute is given as:

T=900+5x

Now, equating both the temperatures, we get

1200-15x=900+5x\\1200-900=15x+5x\\300=20x\\x=\frac{300}{20}=15\ min

Therefore, after 15 minutes, the temperature of both the furnaces will be same.

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The population of a particular city is given by the function P(t) = 27,400(1.07)t, where t is the time in years and P(t) is the
otez555 [7]

Answer:

27,400 is the current population

7% is the rate of increase

The new size is:

  • 38,430 is the population if t is an exponent
  • 146,590 is t is NOT an exponent in the formula you typed

Step-by-step explanation:

To find the population in a future year, use the formula:

P(t) = 27,400(1.07)t

Substitute the value t=5 to find the population in 5 years.

P(t) = 27,400(1.07)t\\P(t) = 27,400(1.07)(5)\\P(t) = 146,590


Or if the equation is supposed to have t as an exponent then look below:

P(t) = 27,400(1.07)^t

Substitute the value t=5 to find the population in 5 years.

P(t) = 27,400(1.07)^t\\P(t) = 27,400(1.07)^(5)\\P(t) = 38,430

This formula is based off the standard formula A=A_0(1+r)^t so r, the rate is 1.07=1+0.07 so r is 7%.

A_0 is the starting population which is 27,400 here.

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3 years ago
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