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3 years ago

Smh I seriously don’t understand how I’m this freaking dumb

Mathematics

2 answers:

Vladimir79 [104]3 years ago

8 0

9. 3x-6=4-2x

First, add 2x to both sides.

5x-6=4

Add 6 to both sides.

5x=10

Divide both sides by 5.

x=2

10. 3x+x=2x+6

Combine like terms.

4x=2x+6

Subtract 2x from both sides.

2x=6

Divide both sides by 2.

x=3

11. 6x=2+x+8

Combine like terms.

6x=10+x

Subtract x from both sides.

5x=10

Divide both sides by 5.

x=2

12. 6x+2-2x=x+8

Combine like terms.

4x+2=x+8

Subtract x from both sides.

3x+2=8

Subtract 2 from both sides.

3x=6

Divide both sides by 3.

x=2

I hope this helps :)

Tema [17]3 years ago

6 0

9) 3x-6 = 4-2x

add 6 to each side:

3x = 10-2x

Add 2x to each side:

5x = 10

Divide both sides by 5:

x = 10/5

x = 2

10) 3x +x = 2x +6

combine like terms on the left side:

4x = 2x +6

subtract 2x from each side:

2x = 6

Divide both sides by 2:

x = 6/2

x =3

11) 6x = 2 + x +8

Combine like terms on the right side:

6x = x +10

Subtract 1x from each side:

5x = 10

Divide both sides by 5:

x = 10/5

x = 2

12) 6x+2-2x = x +8

Combine like terms on the left side:

4x +2 = x +8

Subtract 2 from each side:

4x = x +6

Subtract 1x from each side:

3x = 6

Divide both sides by 3:

x = 6/3

x = 2

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2 years ago

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Answer:

$x=1+\sqrt{3}$ and $x=1-\sqrt{3}$

Step-by-step explanation:

We have been given the parabola with vertex (1, -9) and y intercept at (0, -6).

Now we need to find the x-intercepts of that parabola. So first we begin by finding the equation of parabola using vertex formula:

$y=a\left(x-h\right)^2+k$

Vertex for this formula is given by (h,k)

Compare that with given vertex (1,-9), we get: h=1, k=-9

So plug these into vertex formula:

$y=a\left(x-1\right)^2-9$ ...(i)

Plug given point (0, -6). into (i)

$-6=a\left(0-1\right)^2-9$

$-6=a\left(-1\right)^2-9$

$-6=a\left(1\right)-9$

$-6+9=a$

$3=a$

Plug a=3 into (i)

$y=3\left(x-1\right)^2-9$

Now to find x-intercept, we just plug y=0 and solve for x

$y=3\left(x-1\right)^2-9$

$0=3\left(x-1\right)^2-9$

$9=3\left(x-1\right)^2$

$3=\left(x-1\right)^2$

$\pm \sqrt{3}=x-1$

$1+\pm \sqrt{3}=x$

Hence final answer are

$x=1+\sqrt{3}$ and $x=1-\sqrt{3}$

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3 years ago

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3 years ago

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White raven [17]

Answer:

Step-by-step explanation:

(3+15+21+13)/4 = 13

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13 - 13 = 0

(10+2+8+0)/4 = 5

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3 years ago