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2 years ago

Why isnt 40 divisable by 7 ?

1 answer:

6 0

Actually, 40 is divisible by 7. Any number is divisible by 7. However, 7 does not go into forty evenly. Your quotient would have a remainder since 7 cannot go into 40 an even number of times.

7 goes into 40 5 times evenly (7x5=35) 40-35 is five, so 40 divided by 7 is 5 (remainder 5)

~theLocoCoco

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What desmal is inbetween 1/2 and 3/4

Elis [28]

Answer:

1/2 = 0.5

3/4 = 0.75

Step-by-step explanation:

7 0

2 years ago

Samantha sends her son, Barry, to a preschool center on certain days. The cost of preschool is $45 per day along with a fixed mo

MAXImum [283]

Answer:

Step-by-step explanation:

We are given fixed monthly charge = $70.

The cost of preschool per day = $45.

Number of days = d.

Total cost of d days = cost per day × number of days + fixed monthly charge.

Therefore, we get equation

880 = 45×d+70

Now, we need to solve the equation for d.

Subtracting 70 from both sides, we get

880-70 = 45d +70-70

810=45d

Dividing both sides by 45, we get

$\frac{810}{45} =\frac{45d}{45}$

18=d.

Therefore,<em> 18 days Barry attended preschool last month.</em>

<em>Therefore, correct option is D option.</em>

4 0

2 years ago

The volume of a cone is 339.12 if the radius is 6 meters calculate the height

Natali5045456 [20]

Answer:

9 meters

Step-by-step explanation:

V = 1/3 * pi * r^2 * h

339.12 = 1/3 * pi * 6^2 * h

h = 3 * (339.12)/(36 pi)

h = 9 meters

3 0

3 years ago

Read 2 more answers

Lim x-1 x2 - 1/ sin(x-2)

balu736 [363]

Answer:

$\lim_{x \to 1}\frac{x^2-1}{sin(x-2)}=0$

Explanation:

Assuming the correct expression is to find the following limit:

$\lim_{x \to 1}\frac{x^2-1}{sin(x-2)}$

Use the property the limit of the quotient is the quotient of the limits:

$\lim_{x \to 1}\frac{x^2-1}{sin(x-2)}=\frac{\lim_{x \to 1}x^2-1}{\lim_{x \to 1}sin(x-2)}$

Evaluate the numerator:

$\frac{\lim_{x \to 1}x^2-1}{\lim_{x \to 1}sin(x-2)}=\frac{1^2-1}{\lim_{x \to1}sin(x-2)}=\frac{0}{\lim_{x \to 1}sin(x-2}$

Evaluate the denominator:

Since $\lim_{x \to1}sin(x-2)\neq 0$

$\frac{0}{\lim_{x \to1}sin(x-2)}=0$

4 0

2 years ago

34, 57, 58, 56, 21. Which measure of center best represents the data? Explain why you chose that measure of center.

sveticcg [70]

Answer:

Median

Step-by-step explanation:

The measure of center that best represents the data is median because the data is ordinal, that is it is in ranks. The first is 21, the second is 34, third is 56, fourth is 57 and fifth is 58.

6 0

2 years ago