Answer:
125 mph
Step-by-step explanation:
This can be calculated as a simple rule of 3.
In rule of 3 problems, you need to first identify the measures and whether they are direct or inverse to each other.
If they are direct to each other, if one value increases the other will increase too. For example, lets suppose that the Buffalo Bills have won 3 of 4 games. When there are 8 games, then will have won 6, keeping this proportion. Here, the measures are the number of games and the number of Buffalo Bills wins.
Now if they are inverse to each other, if one value increases the other will decrease. For example, if you travel at 60 mph, you will need 6 hours to arrive at your destination. At 80 mph, you will need less time. So, a the average speed increases, the time you need will decrease.
In this case the speeds is proportional to the time. So, if the time increases, the speed will increase too. It can be calculated by the following rule of 3.
Speed Time
100 mph - 0.8 seconds
x mph - 1 second
x = 100/0.8 = 125 mph.
1.99/32=0.06 an oz
3.69/64=0.05 an oz
5.85/96=0.06 an oz
therefore it is 64 oz
Answer:
I'm not 100% sure but I think it's $6.20
Step-by-step explanation:
First you add up the apples which equals $1.80 then you add up the bananas which equals $1.00 then you add the yogurt together which amounts to $4.50. After that you add all of that together which totals to $7.30.
For the sake of finding the percentage we're gonna move the decimal point to the very end. ( so its 730.0). Now in order to find 15% we have to find 10%. To find 10%, you move the decimal point over one (73.00). So 10% of 730 is 73. 10% + 5% = 15%. And half of 10% is 5%. So, we cut 73 in half so now we have 36.5. Now we add 36.5 to 73 (because 10% + 5%=15%) I'm just gonna round 36.5 to 37, and 73+37= 110. Now we move the decimal point back so its $1.10. Now we subtract $1.10 from $7.30 which is equal to $6.20. So your answer is $6.20.
(I'm rlly bad at explaining things so sorry if this wasnt clear enough. Also I'm not the best at math but I guess I know percentages.)
1. Understand what multi-variable equations are.
Two or more linear equations that are grouped together are called a system. That means that a system of linear equations is when two or more linear equations are being solved at the same time.
[1] For example:
• 8x - 3y = -3
• 5x - 2y = -1
These are two linear equations that you must solve at the same time, meaning you must use both equations to solve both equations.
2. Know that you are trying to figure out the values of the variables, or unknowns.
The answer to the linear equations problem is an ordered pair of numbers that make both of the equations true.
In the case of our example, you are trying to find out what numbers ‘x’ and ‘y’ represent that will make both of the equations true.
• In the case of this example, x = -3 and y = -7. Plug them in. 8(-3) - 3(-7) = -3. This is TRUE. 5(-3) -2(-7) = -1. This is also TRUE.
3. Know what a numerical coefficient is.
The numerical coefficient is simply the number that comes before a variable.[2] You will use these numerical coefficients when using the elimination method. In our example equations, the numerical coefficients are:
• 8 and 3 for the first equation; 5 and 2 for the second equation.
4. Understand the difference between solving with elimination and solving with substitution.
When you use elimination to solve a multivariable linear equation, you get rid of one of the variables you are working with (such as ‘x’) so that you can solve the other variable (‘y’). Once you find ‘y’, you can plug it into the equation and solve for ‘x’ (don’t worry, this will be covered in detail in Method 2).
• Substitution, on the other hand, is where you begin working with only one equation so that you can again solve for one variable. Once you solve one equation, you can plug in your findings to the other equation, effectively making one large equation out of your two smaller ones. Again, don’t worry—this will be covered in detail in Method 3.
5. Understand that there can be linear equations that have three or more variables.
Solving for three variables can actually be done in the same way that equations with two variables are solved. You can use elimination and substitution, they will just take a little longer than solving for two, but are the same process.
