Answer:
Remember, a basis for the row space of a matrix A is the set of rows different of zero of the echelon form of A.
We need to find the echelon form of the matrix augmented matrix of the system A2x=b2
We apply row operations:
1.
- To row 2 we subtract row 1, 4 times.
- To row 3 we subtract row 1, 7 times.
- To row 4 we subtract row 1, 3 times.
- To row 5 we subtract row 1, 6 times.
- To row 6 we subtract row 1, 9 times.
We obtain the matrix
2.
- We subtract row two twice to row three of the previous matrix.
- we subtract 4/3 from row two to row 4.
- we subtract 7/3 from row two to row 5.
- we subtract 10/3 from row two to row 6.
We obtain the matrix
3.
we exchange rows three and four of the previous matrix and obtain the echelon form of the augmented matrix.
Since the only nonzero rows of the augmented matrix of the coefficient matrix are the first three, then the set
is a basis for Row (A2)
Now, observe that the last two rows of the echelon form of the augmented matrix have the last coordinate different of zero. Then, the system is inconsistent. This means that the system has no solutions.
Answer:
d. Anthony rode 14 more miles per week than Malique.
Step-by-step explanation:
Anthony rode (141 mi)/(3 wk) = 47 mi/wk.
Malique rode (165 mi)/(5 wk) = 33 mi/wk.
Anthony rode more miles per week by ...
(47 -33) mi/wk = 14 mi/wk
Anthony rode 14 more miles per week than Malique.
To do this, first start with what you are given. You are given that there is a fixed, or permanent cost of 200 dollars. You are also given that the shirts cost 3$ each. You produce 6 shirts so the equation is 200+3(6)=X. Hope this helps!
Answer:
x=3
Step-by-step explanation:
2x^2= 18
divide the two by 18 —- x^2=9
now x *x= 9 or the square root of 9
Answer:
b. an interval of data
Step-by-step explanation:
A histogram is a chart that plots the distribution of a numeric variable's values as a series of bars. Each bar typically covers a range of numeric values called a bin or class; a bar's height indicates the frequency of data points with a value within the corresponding bin.
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