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3 years ago

Given f(x) = 2x^2 -3x and g(x) = x+4

Mathematics

2 answers:

Alenkasestr [34]3 years ago

8 0

Answer:

2x³ + 5x² - 12x

Step-by-step explanation:

The correct answer doesn't seem to be listed...

(fg)(x) = (2x² - 3x)(x + 4)

Which equals...

2x²(x) + 2x²(4) + (-3x)(x) + (-3x)(4)

Which simplifies to...

2x³ + 8x² - 3x² - 12x

2x³ + 5x² - 12x

Lelechka [254]3 years ago

3 0

Answer:

A is the answer to this question. Hope this helps

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The length of a rectangle is five centimeters less than width. Find the dimensions of the

kondaur [170]

Answer:

w is 10 and l is 5

Step-by-step explanation:

l=w-5

lw=50

w^2-5w-50=(w-10)(w+5) since the negative solution does not make sense w=10 and therefore l is 5 so the length is 5 while the width is 10

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2 years ago

X^3=4 then the value of x=

Law Incorporation [45]

X≈1.5874
(Use the answer in the photo)

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3 years ago

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(-5) -2-8 + 1<br>1-5-2-8<br>helpp plisssssss

Hoochie [10]

Answer:

-14

Step-by-step explanation:

(-5)-2-8+1

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3 years ago

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Suppose that θ is an acute angle of a right triangle and that sec(θ)=52. Find cos(θ) and csc(θ).

insens350 [35]

Answer:

$\cos{\theta} = \dfrac{1}{52}$

$\csc{\theta} = \dfrac{52}{\sqrt{2703}}$

Step-by-step explanation:

To solve this question we're going to use trigonometric identities and good ol' Pythagoras theorem.

a) Firstly, sec(θ)=52. we're gonna convert this to cos(θ) using:

$\sec{\theta} = \dfrac{1}{\cos{\theta}}$

we can substitute the value of sec(θ) in this equation:

$52 = \dfrac{1}{\cos{\theta}}$

and solve for for cos(θ)

$\cos{\theta} = \dfrac{1}{52}$

side note: just to confirm we can find the value of θ and verify that is indeed an acute angle by $\theta = \arccos{\left(\dfrac{1}{52}\right)} = 88.8^\circ$

b) since right triangle is mentioned in the question. We can use:

$\cos{\theta} = \dfrac{\text{adj}}{\text{hyp}}$

we know the value of cos(θ)=1\52. and by comparing the two. we can say that:

length of the adjacent side = 1
length of the hypotenuse = 52

we can find the third side using the Pythagoras theorem.

$(\text{hyp})^2=(\text{adj})^2+(\text{opp})^2$

$(52)^2=(1)^2+(\text{opp})^2$

$\text{opp}=\sqrt{(52)^2-1}$

$\text{opp}=\sqrt{2703}$

length of the opposite side = √(2703) ≈ 51.9904

we can find the sin(θ) using this side:

$\sin{\theta} = \dfrac{\text{opp}}{\text{hyp}}$

$\sin{\theta} = \dfrac{\sqrt{2703}}{52}}$

and since $\csc{\theta} = \dfrac{1}{\sin{\theta}}$

$\csc{\theta} = \dfrac{52}{\sqrt{2703}}$

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3 years ago

What is the area of 4.5 and 5.5cm and 20cm

amm1812

Answer:

6.8

Step-by-step explanation:

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3 years ago