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mylen [45]
2 years ago
13

P and q are different two-digit prime numbers with the same digits, but in reversed order. what is the value of the larger of p

and q?
Mathematics
2 answers:
serious [3.7K]2 years ago
8 0
The set of two-digit primes is {11, 13, 17, 19, 23, 29, 31, 37, 41, 43, 47, 53, 59, 61, 67, 71, 73, 79, 83, 89, 97}

Of that list, the following primes are mirror images of each other
13 and 31
17 and 71
37 and 73
79 and 97
Note: we ignore 11 since 11 flips to 11 which is not distinct from its original

If you're looking for the largest prime of this form, then its 97
If you're looking for the largest gap, then subtract each pair
31-13 = 18
71-17 = 54
73-37 = 36
97-79 = 18
We see that 71 and 17 have the largest gap
Elina [12.6K]2 years ago
7 0
The digits cannot be 2, 4, 6, 5, 8, because those numbers in the one's place do not make a prime number.
of the numbers 1, 3, 7, 9, and largest is 97, and 79 is also a prime number, so the answer is 97
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AlekseyPX
In 1 hour, Antoine travels 1.75 mi by dividing 5.25 by 3. So, after lunch, he hiked 4 hours. 1.75 times 2 is 3.5 mi every hour after lunch. So, 3.5 times 4 is 14 mi. + 5.25 is 19.25 mi., or 19 1/4 miles.
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3 years ago
Above 1700 feet to 2500 feet write compound inequality
alex41 [277]
1700>X<2500

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5 0
3 years ago
Read 2 more answers
A spotlight on the ground shines on a wall 12 m away. If a man 2 m tall walks along the x-axis from the spotlight toward the bui
Sedbober [7]

Answer:

0.675 m/s

Step-by-step explanation:

Let height of shadow= y,CD=x

Height of man=2 m

Speed of man= \frac{dx}{dt}=1. 8 m/s

\triangle ABD\sim\triangle ECD

Therefore, \frac{AB}{EC}=\frac{BD}{CD}

\frac{y}{2}=\frac{12}{x}

xy=24

Differentiate w.r.t t

x\frac{dy}{dt}+y\frac{dx}{dt}=0

x\frac{dy}{dt}=-y\frac{dx}{dt}

\frac{dy}{dt}=-\frac{y}{x}\frac{dx}{dt}

When the man is 4 m from  the building

Then, we have x=12-4=8 m

\frac{dx}{dt}=1.8 m/s

Substitute the values in above equation then, we get

8y=24

y=\frac{24}{8}=3

Substitute the values then we get

\frac{dy}{dt}=-\frac{3}{8}\times 1.8=-0.675 m/s

Hence, the length of his shadow on the building decreasing at the rate 0.675 m/s.

8 0
3 years ago
Someone help with this
elena-14-01-66 [18.8K]

The quadrants are I, II, III, and IV, (meaning 1, 2, 3, and 4). The first quadrant is in the upper right, which has both positive x and positive y values. The second quadrant is the upper left, which has negative x and positive y values. The third quadrant is the lower left, which has both negative x and y values. The fourth quadrant is the lower right, which has positive x and negative y values. Using this knowledge and our positive and negative signs, the following are the answers to questions 1-6.

1) (-4, -2) - Quadrant III, both x and y are negative

2) (0, -7) - This point is actually on the y-axis. The x value is 0 and the y value is -7, so the graph is 7 units down from the origin on the y-axis.

3) (0,0) - This point is the origin, or where the x and y axes cross (the middle of the graph).

4) (6, -9) - This point is in Quadrant IV, because it has a positive x value and a negative y value

5) (3,5) - This point is in Quadrant I, because both the x and y values are positive.

6) (8,0) - This point is on the x-axis. The y-value is zero, so this point is 8 units to the right of the origin between Quadrant I and Quadrant IV.

Using the knowledge presented above, to graph the points given to you in the second part of the problem, first you can figure out what quadrant or part of the graph the point is on. Then, you can count the number of units (squares on the graph) in the right direction (remember that up is positive on the y-axis and down is negative, and to the right is positive on the x-axis and to the left is negative) in order to plot the points. Then, you must connect the points that correspond to the same figure in order to create the figures.

Please comment if you have any questions!

Hope this helps!

7 0
3 years ago
I don’t know how to do any of this
mojhsa [17]

Answer:

The length of x in #1 is 15.57

Step-by-step explanation:

Let's use #1 as an example to teach show you how to do this. In a right triangle we can solve these using trig. In this particular one, we have the measure adjacent to the angle and we are looking for the one opposite of the angle. So we look at all the trig functions and select the one that uses both of those two terms.

Sinα = Opp/Hyp

Tanα = Opp/Adj

Cosα = Adj/Hyp

As you can see, Tan is the function we are looking for. So we plug in all known information into that equation.

Tanα = Opp/Adj -----> Plug in known values

Tan(60) = x/9 ----->Calculate out the trig function

1.73 = x/9 -----> Multiply by the denominator to solve

15.57 = x

3 0
2 years ago
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