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aleksley [76]
3 years ago
5

Find the point(s) of intersection for y = x2 + 3x – 4 and y = 4x + 2

Mathematics
1 answer:
Greeley [361]3 years ago
6 0

Answer:

(6,26)

Step-by-step explanation:

You will take the points and graph them since these are both positive equations they will go up and to the right.

both intersect at (6,26)

also if you forgot how to graph it, I got you

1. find the rate of change (as I will call it) THIS IS YOUR NUMBER NEXT TO THE X!!! this means that the line will go up 4 and over 1 then your whole number, in this example would be 2 is your y-intersect (the place on the y-axis where the line passes) after that you should be able to draw your lines and find the poi!

Please comment if I got something wrong! I don't want to be giving bad advice

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Write each percent as a fraction and as a decimal to the nearest hundredth.
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Each as a fraction 42/100 35/100 18/100 100/100
8 0
3 years ago
The Demand function for a product is given by:
VikaD [51]

Answer:

The average rate of change of Demand between 40 and 175 units sold is of -0.1045.

Step-by-step explanation:

Average rate of change:

The average rate of a function f(x) in an interval [a,b] is given by:

A = \frac{f(b) - f(a)}{b - a}

In this question:

D(q) = -0.0003q^2 - 0.04q + 23.56

What is the average rate of change of Demand between 40 and 175 units sold?

a = 40, b = 175. So

D(40) = -0.0003*40^2 - 0.04*40 + 23.56 = 21.48

D(175) = -0.0003*175^2 - 0.04*175 + 23.56 = 7.3725

So

A = \frac{f(b) - f(a)}{b - a} = \frac{7.3725 - 21.48}{175 - 40} = -0.1045

The average rate of change of Demand between 40 and 175 units sold is of -0.1045.

3 0
3 years ago
If r(X)=2-x^2 and w(X)=X-2, what is the range of (w*r)(X)
slega [8]
The given function are
r(x) = 2 - x²    and     w(x) = x - 2
<span>(w*r)(x) can be obtained by multiplying the both function together
</span>
So, <span>(w*r)(x) = w(x) * r(x) = (x-2)*(2-x²)</span>
<span>(w*r)(x) = x (2-x²) - 2(2-x²)</span>
            = 2x - x³ - 4 + 2x²

∴ <span>(w*r)(x) = -x³ + 2x² + 2x - 4
</span>

<span>It is a polynomial function with a domain equal to R
</span>
The range of <span>(w*r)(x) can be obtained by graphing the function
</span>
To graph (w*r)(x), we need to make a table between x and (w*r)(x)

See the attached figure which represents the table and the graph of <span>(w*r)(x)
</span>

As shown in the graph the range of <span>(w*r)(x) is (-∞,∞)
</span>

8 0
3 years ago
Read 2 more answers
If the point (2,5) is on the graph of an equation, which statement must be
Hunter-Best [27]

Answer: D

Step-by-step explanation:

The values x = 2 and y = 5 make the equation true.

4 0
3 years ago
Val needs to find the area enclosed by the figure. The figure is made by attaching semicircles to each side of a 58​-by-58 squar
Savatey [412]

Answer:

We need to find the area of the semicircles + the area of the square.

The area of a square is equal to the square of the lenght of one side.

As = L^2 = 58m^2 = 3,364 m^2

Now, each of the semicircles has a diameter of 58m, and we have that the area of a circle is equal to:

Ac = pi*(d/2)^2 = 3.14*(58m/2)^2 = 3.14(27m)^2 = 2,289.06m^2

And the area of a semicircle is half of that, so the area of each semicircle is:

a =  (2,289.06m^2)/2 = 1,144.53m^2

And we have 4 of those, so the total area of the semicircles is:

4*a = 4* 1,144.53m^2 = 4578.12m^2

Now, we need to add the area of the square 3,364 m^2 + 4578.12m^2 = 7942.12m^2

This is nothing like the provided anwer of Val, so the numbers of val may be wrong.

4 0
3 years ago
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