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aivan3 [116]
3 years ago
7

After eating a large meal, which branch of your nervous system is activated? after eating a large meal, which branch of your ner

vous system is activated? sensory somatic (motor) enteric sympathetic
Biology
2 answers:
Ne4ueva [31]3 years ago
6 0
<h2>Sensory Somatic (Motor) Enteric Sympathic </h2>

After eating a large meal, parasympathetic nerves of your nervous system is activated. Parasympathetic nervous system is the type of autonomic nervous system. It is known as rest. In this type of nervous system, energy is conserved as it slows the heart rate, increases intestinal and gland activity, and relaxes sphincter muscles in the gastrointestinal tract.


Vanyuwa [196]3 years ago
3 0

Parasympathetic nervous

Parasympathetic nervous system is known to be one of the two divisions of the autonomic nervous system and it is responsible for the stimulation of rest and digest activities that usually occur when the body is at rest after eating which includes salivation, urination, sexual arousal and digestion.

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A population of 1,000 birds exists on a small Pacific island. Some of the birds are yellow, a characteristic determined by a rec
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Option B

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Please see the attachment

4 0
3 years ago
In a population of 150 toads, poisonous (P) is dominant over non-poisonous (p). According to the Hardy-Weinberg equation, the ex
aalyn [17]

Answer: Χ²=8.18

Explanation: In this population, the frequency of homozygote poisonous toads is:

p^{2} =\frac{100}{150}

p^{2} = 0.667

p = \sqrt{0.667}

p=0.82

For the homozygote non-poisonous toads:

q^{2} = \frac{5}{150}

q^{2} =0.034

q = \sqrt{0.034}

q = 0.18

The frequency for heterozygote poisonous toad, we can use the Hardy-Weinberg equation: p^{2} + 2pq + q^{2} = 1, in which, heterozygote frequency is given by 2pq

2pq = 2*0.82*0.18 = 0.3

Now, to compute the chi-square test, follow the instructions:

1) Find the observed values: in this case, they are the found frequency:

0.82       0.3         0.18

2) Find the expected values: As the question mentioned, the expected proportion is:

16            8             1

3) Subtract the observed value from the expected value:

0.82 - 16 = - 0.184          0.3 - 8 = -7.7             0.18 - 1 = - 0.818

4) Square each value from above:

(-0.184)² = 0.034            (-7.7)² = 59.3                 (-0.818)² = 0.77

5) Divide each value by expected value:

\frac{0.034}{16} = 0.0021                   \frac{59.3}{8} = 7.41                      \frac{0.77}{1} = 0.77

6) Add all the values and we will have the chi-square test:

Χ² = 0.0021 + 7.41 + 0.77 = 8.18

The chi-square test is Χ² = 8.18

8 0
3 years ago
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