An integer may be a multiple of 3.
An integer may be 1 greater than a multiple of 3.
An integer may be 2 greater than a multiple of 3.
It is redundant to say an integer is 3 greater than a multiple of 3 (that's just a multiple of 3, we've got it covered). Same for 4, 5, 6, 7...
Let's consider a number which is a multiple of 3. Clearly, we can write 3+3+3+3+... until we reach the number. It can be written as only 3's.
Let's consider a number which is 2 greater than a multiple of 3. If we subtract 5 from that number, it'll be a multiple of 3. That means we can write the number as 5+3+3+3+3+... Of course, the number must be at least 8.
Let's consider a number which is 1 greater than a multiple of 3. If we subtract 5 from that number, it'll be 2 greater than a multiple of 3. If we subtract another 5, it'll be a multiple of 3. That means we can write the number as 5+5+3+3+3+3+... Of course, the number must be at least 13.
That's it. We considered all the numbers. We forgot 9, 10, 11, and 12, but these are easy peasy.
Beautiful question.
34 / .40 = 85
I hope this helps :)
Answer:
Multiply both sides by 2
Subtract l from both sides
Divide each side by 3
(2R -l)/3 =w
Step-by-step explanation:
R = (l+3w)/2
Multiply both sides by 2
2R = 2* (l+3w)
2R = l+3w
Subtract l from both sides
2R - l = l-l +3w
2R -l = 3w
Divide each side by 3
(2R-l) /3 = 3w/3
(2R -l)/3 =w
a baseball team scored the following number of runs in its game this season: 6, 2, 5, 9, 11, 4, 5, 8, 6, 7, 5. there is one more
frez [133]
After the season, 12 games would be played, and you need to know this to work out the mean
Let's call the number of points needed for a 6 point average 'x'
The mean would be: 6 + 2 + 5 + 9 + 11 + 4 + 5 + 8 + 6 + 7 + 5 + x = 12 * 6
Simply put:
68 + x = 72
Then simplify it
x = 4
They would need 4 points to end the season with an average of 6 points
Answer:
-1
Step-by-step explanation:
2 - 3 = -1
