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morpeh [17]
3 years ago
14

Is (–3, 6) a solution to this system of equations? 10x − 5y = 16 x + y = 3

Mathematics
1 answer:
nalin [4]3 years ago
3 0

wellllllllllll when you plug in (-3) for x and (6) for y

10(-3)-5(6)=16

-30-30=16

-60=16

as you can see -60 is not equal to 16 so that means (-3,6) is not a solution :)

there is not point in trying the second equation cause we already know it is false :))

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1. Solve for n: n+5/16 = -1 <br>(A) 96 <br>(B) -96 <br>(C) 21 <br>(D) -21​
kati45 [8]
The answer is D -21
3 0
3 years ago
A ball is thrown upward from the top of a 40 foot high building at a speed of 80 feet per second. The ball's height above
tekilochka [14]

it takes 5 seconds to reach a height of 40 ft. and It takes 2.5 seconds to reach maximum height.

Let h(t) represent the height of the ball at time t.

Given that the height is given by:

h(t) = -16t² + 80t + 40

1) For the ball to reach a height 0f 40 ft, h(t) = 40, hence:

40 = -16t² + 80t + 40

16t² - 80t = 0

t(t - 5) = 0

t = 0 or t = 5

Hence it takes 5 seconds to reach a height of 40 ft.

2) The maximum height is at h'(t) = 0,

h'(t) = -32t + 80

-32t + 80 = 0

32t = 80

t = 2.5

It takes 2.5 seconds to reach maximum height.

Find out more at: brainly.com/question/11535666

5 0
2 years ago
2) Richard, Henry and Gavin share some sweets in the ratio 4:1:3. Richard gets 7 more sweets
sineoko [7]

Answer:

6

Step-by-step explanation:

Richard gets 7 more sweets than Gavin which would probably make Richard have the most so in total he should have around 8 whilst Gavin has 1 so right now we have 4:1:?. Basing off the fact that Richard would have the most sweets Henry would have to have 6 sweets to be able to divide half of it for 3. 4:1:3

5 0
2 years ago
A runner runs around a circular track. He completes one lap at a time of t = 269 s at a constant speed of v = 4.6 m/s. What is t
AURORKA [14]

Answer:

\boxed{\text{197 m}}

Step-by-step explanation:

The formula relating distance (d), speed (s), and time (t) is

d = st

1. Calculate the distance

d = 269 s × 4.6 m·s⁻¹ = 1240 m

2.Calculate the track radius

The distance travelled is the circumference of a circle

\begin{array}{rcl}C & = & 2 \pi r\\1240 & = & 2 \pi r\\\\r & = & \dfrac{1240}{2 \pi }\\\\& = & 197\\\end{array}\\\text{The radius of the track is }\boxed{\textbf{197 m}}

5 0
3 years ago
Simplify 7/x+2-4/x-5
lesantik [10]
-3(x-1)/x would be your answer
3 0
3 years ago
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