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morpeh [17]
3 years ago
14

Is (–3, 6) a solution to this system of equations? 10x − 5y = 16 x + y = 3

Mathematics
1 answer:
nalin [4]3 years ago
3 0

wellllllllllll when you plug in (-3) for x and (6) for y

10(-3)-5(6)=16

-30-30=16

-60=16

as you can see -60 is not equal to 16 so that means (-3,6) is not a solution :)

there is not point in trying the second equation cause we already know it is false :))

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Answer:

y =112

Step-by-step explanation:

Given

The attached triangle

Required

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The attached triangle is isosceles; so:

x - 5=34

Also, we have:

y + x - 5 + 34=180 --- angles in a triangle

Substitute: x - 5=34

y + 34 + 34=180

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1

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4 years ago
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3 years ago
What is the volume of the composite figure? Explain your work. A complete answer should include how you broke up the figure, whi
Sphinxa [80]

Answer:

15,000\:\mathrm{mm^3}

Step-by-step explanation:

The composite figure consists of a square prism and a trapezoidal prism. By adding the volume of each, we obtain the volume of the composite figure.

The volume of the square prism is given by V=s^2\cdot h, where s is the base length and h is the height. Substituting given values, we have: V=14^2\cdot 30=196\cdot 30=5,880\:\mathrm{mm^3}

The volume of a trapezoidal prism is given by V=\frac{b_1+b_2}{2}\cdot l\cdot h, where b_1 and b_2 are bases of the trapezoid, l is the length of the height of the trapezoid and h is the height. This may look very confusing, but to break it down, we're finding the area of the trapezoid (base) and multiplying it by the height. The area of a trapezoid is given by the average of the bases (\frac{b_1+b_2}{2}) multiplied by the trapezoid's height (l).

Substituting given values, we get:

V=\frac{14+24}{2}\cdot (30-14)\cdot 30,\\V=19\cdot 16\cdot 30=9,120\:\mathrm{mm^3}}

Therefore, the total volume of the composite figure is 5,880+9,120=\boxed{15,000\:\mathrm{mm^3}} (ah, perfect)

Alternatively, we can break the figure into a larger square prism and a triangular prism to verify the same answer:

V=30^2\cdot 14+\frac{1}{2}\cdot10\cdot 16\cdot 30=\boxed{15,000\:\mathrm{mm^3}}\checkmark

8 0
3 years ago
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