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2 years ago

Dan thinks of a number

Mathematics

1 answer:

puteri [66]2 years ago

5 0

Answer:

-1

Step-by-step explanation:

2 - 3 = -1

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How do i find LM? On number 2 .

Masja [62]

Given: KL is a tangent to the circle.
LM is another tangent to the circle.

We can use the tangent meeting at an external point theorem.
<em>Theorem</em>: <em>The tangent segments to a circle from an external point are equal.
</em>
Thus, we can say KL = LM, as they lie on a common circle, and are tangents to such circle.

4x - 2 = 3x + 3
4x - 3x = 3 + 2
x = 5

Since LM is 3x + 3, we can substitute the value of x to LM to render:
3(5) + 3 = 18

Thus, LM = KL = 18 units.

4 0

3 years ago

Hi, can someone please help me with this question, I'm a bit baffled.

liq [111]

-1(3x-2y=27)
3x-y=24
-3x+2y=-27
+3x-y = 24
y=-3
3x-(-3)=24
3x+3=24
-3. -3
3x=21
/3. /3
X=7
Hope that helps

7 0

2 years ago

Read 2 more answers

Help please :) show work

Tju [1.3M]

60% of 6,800 is 4,080 so they sold 4,080. 60

6 0

2 years ago

Read 2 more answers

In a basketball tournament, team A scored 6 more points than 3 times as many points as team B scored. Team C scored 45 more poin

velikii [3]

Answer:

"Team C scored 130 points."

Step-by-step explanation:

Let x represent how many points team B scored.

Team A: 3x + 6

Team B: x

Team C: x + 45

Total: 476 points

476 = (x) + (3x + 6) + (x + 45)

476 = x + 3x + 6 + x + 45

476 = 5x + 51

425 = 5x

x = 85

Team A:

3(85) + 6

= 261 pts

Team B:

= 85 pts

Team C:

(85) + 45

= 130 points

4 0

2 years ago

Read 2 more answers

Suppose that in a senior college class of 500500 students, it is found that 179179 smoke, 228228 drink alcoholic beverages, 1

olga2289 [7]

Answer: a) 0.16, b) 0.058, and c) 0.856.

Step-by-step explanation:

Since we have given that

Number of students = 500

Number of students smoke = 179

Number of students drink alcohol = 228

Number of students eat between meals = 119

Number of students eat between meals and drink alcohol = 59

Number of students eat between meals and smoke = 72

Number of students engage in all three = 30

a) Probability that the student smokes but does not drink alcohol is given by

$P(S-A)=P(S)-P(S\cap A)\\\\P(S-A)=\dfrac{179}{500}-\dfrac{99}{500}\\\\P(S-A)=\dfrac{179-99}{500}\\\\P(S-A)=\dfrac{80}{500}\\\\P(S-A)=0.16$

b) eats between meals and drink alcohol but does not smoke.

$P((M\cap A)-S)=P(M\cap A)-P(M\cap S\cap A)\\\\P((M\cap A)-S)=\dfrac{59}{500}-\dfrac{30}{500}\\\\P((M\cap A)-S)=\dfrac{59-30}{500}\\\\P((M\cap A)-S)=\dfrac{29}{500}\\\\P((M\cap A)-S)=0.058$

c) neither smokes nor eats between meals.

$P(S'\cap M')=1-P(S\cup M)\\\\P(S'\cap M')=1-\dfrac{72}{500}\\\\P(S'\cap M')=\dfrac{500-72}{500}\\\\P(S'\cap M')=\dfrac{428}{500}=0.856$

Hence, a) 0.16, b) 0.058, and c) 0.856.

5 0

2 years ago