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3 years ago

Jerome burned 75 calories in 15 minutes on a stationary bike. How many calories will he burn in 25 minutes

1 answer:

7 0

Is jerome also on stationary bicycle for next 10 minute?? if yes then he burn 125 calories at the average of 5 calorie per minute

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The circumference of a circle is 11pi ft. find its diameter, in feet

mixer [17]

Answer:

The diameter would be 11 feet

Step-by-step explanation:

C = pi * d

we don't know D so we rearrange the equation to solve for D by dividing both sides by pi:

C/pi = d

Now we plug in everything

11pi/pi = d

The pi cancel each other out leaving with 11 feet

Therefore D = 11 feet

3 0

3 years ago

What is x? -3(52)=-3(x)+-3(2)

krek1111 [17]

Answer:

x = 50

Step-by-step explanation:

-3(52)=-3(x)+-3(2)

Divide both sides by -3

52 = x + 2

x = 50

8 0

3 years ago

d = {x|x is a whole number} e = {x|x is a perfect square between 1 and 9} f = {x|x is an even number greater than or equal to 2

Alexxandr [17]

$D=\{0;\ 1;\ 2;\ 3;\ 4;...\}\\E=\{4\}\\F=\{2;\ 4;\ 6;\ 8\}\\\\D\ \cap\ F=\{2;\ 4;\ 6;\ 8\}=F\to\boxed{c.}\\conclusion\ F\subset D$

5 0

3 years ago

Read 2 more answers

(1/1+sintheta)=sec^2theta-secthetatantheta pls help me verify this

Xelga [282]

Answer:

See Below.

Step-by-step explanation:

We want to verify the equation:

$\displaystyle \frac{1}{1+\sin\theta} = \sec^2\theta - \sec\theta \tan\theta$

To start, we can multiply the fraction by (1 - sin(θ)). This yields:

$\displaystyle \frac{1}{1+\sin\theta}\left(\frac{1-\sin\theta}{1-\sin\theta}\right) = \sec^2\theta - \sec\theta \tan\theta$

Simplify. The denominator uses the difference of two squares pattern:

$\displaystyle \frac{1-\sin\theta}{\underbrace{1-\sin^2\theta}_{(a+b)(a-b)=a^2-b^2}} = \sec^2\theta - \sec\theta \tan\theta$

Recall that sin²(θ) + cos²(θ) = 1. Hence, cos²(θ) = 1 - sin²(θ). Substitute:

$\displaystyle \displaystyle \frac{1-\sin\theta}{\cos^2\theta} = \sec^2\theta - \sec\theta \tan\theta$

Split into two separate fractions:

$\displaystyle \frac{1}{\cos^2\theta} -\frac{\sin\theta}{\cos^2\theta} = \sec^2\theta - \sec\theta\tan\theta$

Rewrite the two fractions:

$\displaystyle \left(\frac{1}{\cos\theta}\right)^2-\frac{\sin\theta}{\cos\theta}\cdot \frac{1}{\cos\theta}=\sec^2\theta - \sec\theta \tan\theta$

By definition, 1 / cos(θ) = sec(θ) and sin(θ)/cos(θ) = tan(θ). Hence:

$\displaystyle \sec^2\theta - \sec\theta\tan\theta \stackrel{\checkmark}{=} \sec^2\theta - \sec\theta\tan\theta$

Hence verified.

8 0

2 years ago

Simplify.

Softa [21]

Answer:

√12-2/5×√75

2√2-2/5×5√3

2√2-2√3

2(√(2×3)

2√6

3 0

2 years ago

Read 2 more answers