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Setler [38]
3 years ago
10

A quantity increases according to the exponential function y(t)=y0ekt. a. What is the tripling time? b. What is the time require

d for the quantity to increase p-fold?
Mathematics
1 answer:
Alex73 [517]3 years ago
7 0

Answer:

Step-by-step explanation:

Given

A quantity is increasing according to

y(t)=y_0e^{kt}

time taken to triple the initial Quantity

i.e. y(t)=3 y_0

3y_0=y_0e^{kt}

3=e^{kt}

Taking log on both side

\ln 3=kt

t=\frac{\ln 3}{k}

(b)Time required to increase P-fold

i.e. y(t)=Py_0

Py_0=y_0e^{kt}

P=e^{kt}

taking log both sides

t=\frac{\ln P}{k}    

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Answer:

s^2 = \frac{(1.48-1.502)^2 +(1.45-1.502)^2 +(1.54-1.502)^2 +(1.52-1.502)^2 +(1.52-1.502)^2}{5-1} =0.00132

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Step-by-step explanation:

For this case we have the following data:

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The first step for this cae is find the sample mean with the following formula:

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s^2 = \frac{(1.48-1.502)^2 +(1.45-1.502)^2 +(1.54-1.502)^2 +(1.52-1.502)^2 +(1.52-1.502)^2}{5-1} =0.00132

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