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il63 [147K]
3 years ago
11

This was my very last homework question and i'm stumped. log_4(x+1)-log_4(x)=3

Mathematics
1 answer:
mixas84 [53]3 years ago
4 0

\log_4(x+1)-\log_4x=3 \qquad(x>0)\\ \log_4\dfrac{x+1}{x}=3\\ \dfrac{x+1}{x}=4^3\\ \dfrac{x+1}{x}=64\\ x+1=64x\\ 63x=1\\ x=\dfrac{1}{63}

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Answer:

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Step-by-step explanation:

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Start by looking at the difference in the X and Y coordinates.

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You could calculate the length of the line using pythagorian's theorem, but that's not needed. Simply use similar triangles. We have a right triangle with legs of length 16 and length 8. We want a similar triangle that is 1/8th as large (to get the desired 1 to 7 ratio). So divide both legs by 8, getting lengths of 16/8 = 2, and 8/8 = 1.

Now add those calculated offsets to point A.

A has an X coordinate of -4 and B has an X coordinate of 12 and the X coordinate for C must be between those limits. So calculate -4 + 2 = -2 to get the X coordinate for C.

The Y coordinate of A is 7 and the Y coordinate of B is -1. And since the Y coordinate must be between then, you have 7 - 1 = 6.

So the coordinates for C is (-2, 6)

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3 years ago
What is another way to write 42 + 63
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