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zzz [600]
3 years ago
12

Does a=2.1 b=7.2 c=7.5 form a right triangle

Mathematics
2 answers:
Anna007 [38]3 years ago
6 0

Answer:

Yes

Step-by-step explanation:

If the longest side squared is equal to the sum of the squares on the other 2 sides then they form a right triangle

longest side = 7.5

7.5² = 56.25

2.1² + 7.2² = 4.41 + 51.84 = 56.25

Thus the 3 values form a right triangle.

zaharov [31]3 years ago
5 0

Answer: Yes, the three measurements form a right angled triangle

Step-by-step explanation: A right angled triangle can be solved by the Pythagoras theorem, that is, when one side is missing. The formula is

AC^2 = AB^2 + BC^2

(The square of the longest side equals to the sum of the square of the other two sides)

Where AC is the longest side and AB and BC are the other two sides.

In the question given, the longest side is 7.5, and so substituting for the values, we can write out the Pythagoras theorem as follows;

7.5^2 = 7.2^2 + 2.1^2

56.25 = 51.84 + 4.41

56.25 = 56.25

Since the Left Hand Side equals to the Right Hand Side, then the dimensions given in the question forms a right angled triangle

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Answer:

34

Step-by-step explanation:

Hypotenuse is the longest side

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Una lancha que viaja a 10 m/s pasa por debajo de un puente 3 segundos después que ha pasado un bote que viaja a 7 m/s, ¿después
ExtremeBDS [4]

Answer:

La lancha y el bote se encontrarán a 70 metros de distancia del puente.

Step-by-step explanation:

Sea el punto debajo del puente el punto de referencia y que ambas lanchas se desplazan a velocidad a continuación, las ecuaciones cinemáticas para cada embarcación son presentadas a continuación:

Bote a 7 metros por segundo

x_{A} = x_{o}+v_{A}\cdot t (Ec. 1)

Lancha a 10 metros por segundo

x_{B} = x_{o}+v_{B}\cdot (t-3\,s) (Ec. 2)

Donde:

x_{o} - Posición debajo del puente, medido en metros.

x_{A}, x_{B} - Posición final de cada embarcación, medido en metros.

v_{A}, v_{B} - Velocidad de cada embarcación, medida en metros por segundo.

t - Tiempo, medido en segundos.

Para determinar la posición en la que ambas embarcaciones se encuentran, se debe determinar el instante en que ocurre a partir de la siguiente condición: x_{A} = x_{B}

Igualando (Ec. 1) y (Ec. 2) se tiene que:

v_{A}\cdot t = v_{B}\cdot (t-3\,s)

Ahora despejamos el tiempo:

3\cdot v_{B} = (v_{B}-v_{A})\cdot t

t = \frac{3\cdot v_{B}}{v_{B}-v_{A}}

Si sabemos que v_{B} = 10\,\frac{m}{s} y v_{A} = 7\,\frac{m}{s}, entonces:

t = \frac{3\cdot \left(10\,\frac{m}{s} \right)}{10\,\frac{m}{s}-7\,\frac{m}{s}}

t = 10\,s

Ahora, la posición de encuentro es: (x_{o} = 0\,m, v_{A} = 7\,\frac{m}{s} y t = 10\,s)

x_{A} = 0\,m + \left(7\,\frac{m}{s} \right)\cdot (10\,s)

x_{A} = 70\,m

La lancha y el bote se encontrarán a 70 metros de distancia del puente.

6 0
3 years ago
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Answer:Jeff's restaurant

Step-by-step explanation:

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What is the value of x?
Angelina_Jolie [31]

Answer:

x = 5.4

Step-by-step explanation:

3/x = 4/7.2

cross-multiply:

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