20 times .06. Then you add that to 20. Subtract the total of all the supplies needed from 21.20. That will equal your change. Then subtract 9.37 from 21.20. That will be the cost. <span />
Answer:
The 99% confidence interval for the proportion of athletes who graduate is (0.5309, 0.7323).
Step-by-step explanation:
In a sample with a number n of people surveyed with a probability of a success of
, and a confidence level of
, we have the following confidence interval of proportions.
![\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}](https://tex.z-dn.net/?f=%5Cpi%20%5Cpm%20z%5Csqrt%7B%5Cfrac%7B%5Cpi%281-%5Cpi%29%7D%7Bn%7D%7D)
In which
z is the zscore that has a pvalue of
.
For this problem, we have that:
![n = 152, \pi = \frac{96}{152} = 0.6316](https://tex.z-dn.net/?f=n%20%3D%20152%2C%20%5Cpi%20%3D%20%5Cfrac%7B96%7D%7B152%7D%20%3D%200.6316)
99% confidence level
So
, z is the value of Z that has a pvalue of
, so
.
The lower limit of this interval is:
![\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.6316 - 2.575\sqrt{\frac{0.6316*0.3684}{152}} = 0.5309](https://tex.z-dn.net/?f=%5Cpi%20-%20z%5Csqrt%7B%5Cfrac%7B%5Cpi%281-%5Cpi%29%7D%7Bn%7D%7D%20%3D%200.6316%20-%202.575%5Csqrt%7B%5Cfrac%7B0.6316%2A0.3684%7D%7B152%7D%7D%20%3D%200.5309)
The upper limit of this interval is:
![\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.6316 + 2.575\sqrt{\frac{0.6316*0.3684}{152}} = 0.7323](https://tex.z-dn.net/?f=%5Cpi%20%2B%20z%5Csqrt%7B%5Cfrac%7B%5Cpi%281-%5Cpi%29%7D%7Bn%7D%7D%20%3D%200.6316%20%2B%202.575%5Csqrt%7B%5Cfrac%7B0.6316%2A0.3684%7D%7B152%7D%7D%20%3D%200.7323)
The 99% confidence interval for the proportion of athletes who graduate is (0.5309, 0.7323).
Since you know that when x = 2, y = 8, when you replace x with xb:
<span>8=(xb<span>)3</span></span>
x has been replaced by xb, so xb must equal 2
and then substituting in 0.5 for x, you can solve for b
<span><span>0.5b=2</span></span>
No estoy segura de lo más bello de la verdad que no te entiendo porque tú sabes lo qué quieres que
15 / 20 = 3 × 5 / 4 × 5
simplify 5 from The Denominator and The numerator
= 3 / 4