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Lyrx [107]
3 years ago
14

The distance around the outside of someone’s property is 900 feet. The length and the width are equal. Find the dimensions

Mathematics
1 answer:
belka [17]3 years ago
5 0
Since the Length and Width are equal, and together equal 900 ft, simply divide 900 by 2 which equals 450
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I need help with Multiplication Properties of Exponents desperately!! I've tried to solve both problems repeatedly and I cannot
Yuliya22 [10]

Answer:

1) x= -36.

2) x = 0.

Step-by-step explanation:

1) Taking the 3rd power to both sides and using the following exponent law:

\left(a^b\right)^c = a^{bc}

we get:

\left(\left(m^{x}\right)^{\frac{1}{3}}\right)^3 = \left(m^{-12}\right)^3 \\ m^x = m^{-36}

So this tells us that x = -36.

2) We can distribute the power inside every term. So the left side becomes:

\left(3x^3y^x\right)^3 = 3^3\left(x^3)^3y^{3x} = 27x^9y^{3x}

Now, the trick here is to remember that y^0 = 1, so replacing 1 with y^0, which then gives us:

27x^9y^{3x} = 27x^9y^{0}, telling us that 3x = 0 and thus, x = 0.

7 0
3 years ago
Jun-seo notices that there are 13 right-handed players on his baseball team and 2left-handed players.
IRISSAK [1]

Step-by-step explanation:

ratio of the right handed to left handed is 13 to 2

8 0
3 years ago
Plzzzz help!! Me find x
vivado [14]

Answer:

x=-4

Step-by-step explanation:

These two angles have to equal 180 because they are opposite of each other. Therefore, the equation will be 129+x+x+59=180. You add all common terms. 2x+188=180. You want to isolate x so you have to subtract both sides by 188. Therefore, the equation will be 2x=-8. Divide both sides by 2 to isolate x. x=-8/2. This is equal to x=-4.

If this has helped please mark as brainliest

3 0
3 years ago
The level of CO2 emissions, f(x), in metric tons, from the town of Fairfax x years after they started recording is shown in the
Temka [501]
1) The average increase in the level of CO2 emissions per year from years 2 to 4 is:
Average=[f(4)-f(2)]/(4-2)=(29,172.15-26,460)/2=2,712.15/2=1,356.075 metric tons. The first is false.

2) The average increase in the level of CO2 emissions per year from years 6 to 8 is:
Average=[f(8)-f(6)]/(8-6)=(35,458.93-32,162.29)/2=3,296.64/2=1,648.32 metric tons. The second is false.

3) The average increase in the level of CO2 emissions per year from years 4 to 6 is:
Average=[f(6)-f(4)]/(6-4)=(32,162.29-29,172.15)/2=2,990.14/2=1,495.07 metric tons. The third is false.

4) The average increase in the level of CO2 emissions per year from years 8 to 10 is:
Average=[f(10)-f(8)]/(10-8)=(39,093.47-35,458.93)/2=3,634.54/2=1,817.27 metric tons. The fourth is true.

Answer: Fourth option: The average increase in the level of CO2 emissions per year from years 8 to 10 is 1,817.27 metric tons.
7 0
3 years ago
A/75=15/100<br> help me in this :(
Svetach [21]

a / 75 = 15 / 100

100a = 75 * 15       [cross multiplication]

a = 11.25

i hope this helps!!! :D

4 0
2 years ago
Read 2 more answers
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