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4 years ago

I really need this can someone help solve asap!!!

Mathematics

1 answer:

Kryger [21]4 years ago

4 0

Answer: to find this answer .we need to do pegothogs property

Step-by-step explanation:

30° + 90° = 90 (because it is right angle )

120° - 90° = 30°

Plz mark me as brainlist

thank you :-)

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9. Identify the correct property being shown.

BaLLatris [955]

Answer:

-16.4, (commutative property)

Step-by-step explanation:

(add, because they are both negatives) -5.2+(-8.4)= -13.6

Then add the (-2.8): -13.6 + (-2.8) = -16.4

Thats your first equation!!!

do the same thing for the other one, and by the way it the same answer.

Its commutative prop because its just switching positions and its adding negatives.

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The SAT scores have an average of 1200 with a standard deviation of 60. A sample of 36 scores is selected. a) What is the probab

LiRa [457]

Answer:

a) 0.0082

b) 0.9987

c) 0.9192

d) 0.5000

e) 1

Step-by-step explanation:

The question is concerned with the mean of a sample.

From the central limit theorem we have the formula:

$z=\frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }$

a) $z=\frac{1224-1200}{\frac{60}{\sqrt{36} } }=2.40$

The area to the left of z=2.40 is 0.9918

The area to the right of z=2.40 is 1-0.9918=0.0082

$\therefore P(\bar X\:>\:1224)=0.0082$

b) $z=\frac{1230-1200}{\frac{60}{\sqrt{36} } }=3.00$

The area to the left of z=3.00 is 0.9987

$\therefore P(\bar X\:$

c) The z-value of 1200 is 0

The area to the left of 0 is 0.5

$z=\frac{1214-1200}{\frac{60}{\sqrt{36} } }=1.40$

The area to the left of z=1.40 is 0.9192

The probability that the sample mean is between 1200 and 1214 is

$P(1200\:$

d) From c) the probability that the sample mean will be greater than 1200 is 1-0.5000=0.5000

e) $z=\frac{73.46-1200}{\frac{60}{\sqrt{36} } }=-112.65$

The area to the left of z=-112.65 is 0.

The area to the right of z=-112.65 is 1-0=1

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3 years ago

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Step-by-step explanation:

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