Solutions
1) <span>Add the whole numbers first ( 7 and 2 )
</span><span>9+<span>7/8</span>+<span>11/12
2) </span></span>Find the Least Common Denominator (LCD) of
<span><span>7 / 8</span>,<span>11 / 12
</span></span>
Start by Listing Multiples
List out all multiples of each denominator, and find the first common one.
8 : <span><span>8,16,24</span>
</span>
12 : <span>12,24
</span>
Therefore, the LCD is <span>24
</span>Method 2: By Prime Factors
List all prime factors of each denominator, and find the union of these primes.
8 : <span>2,2,2
</span>
12 : <span>2,2,3
</span>
Therefore, the LCD is <span>2×2×2×3=24
3) </span>Make the denominators the same as the LCD
<span>9+<span><span>7×3 / </span><span>8×3</span></span>+<span><span>11×2 / </span><span>12×2
</span></span></span>4) Simplify. Denominators are now the same
<span>9+<span>21 / 24</span>+<span>22 / 24
5) J</span></span>oin the denominators
<span>9+<span><span>21+22 / </span>24</span></span>
6) Simplify
<span>9+<span>43 / 24
7) </span></span>Convert 43 / 24 <span>to mixed fraction
</span><span>9+1 <span>19 / 24
8) </span></span>Simplify
<span><span>10 <span>19 / 24</span></span></span>
Answer:7
Step-by-step explanation:
This question is on the ukmt junior maths challenge which I'm doing now, out of the options given I got 7, because 2+4+6+5+(5×20)+(7×7)= 166, (then dividing that by the number of numbers to get the mean) so 166÷31= 5.354.....
Also the 3 has a recurring symbol above it
The 7 is times seven so uh yeah<3
the top number is the exponent, the bottom number is the root.
15)
=
16)
= ![16\sqrt[4]{x^{3} }](https://tex.z-dn.net/?f=16%5Csqrt%5B4%5D%7Bx%5E%7B3%7D%20%7D)
Answer:
21.84
Step-by-step explanation:
5.46
/
.25
21.84
Answer:
(2, 5)
Step-by-step explanation:
I plugged into a graphing calculator and just did it by looking at how many spots it was down or over from the midpoint and then did the opposite. I really don't know how to explain it so I am sorry for that, but I hope this helps.