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3 years ago

What is the volume of the regular pyramid below 81, 10,10

Mathematics

1 answer:

GarryVolchara [31]3 years ago

4 0

Volume of a pyramid is calculated by L×W×H÷3. Which means 81× 10× 10 ÷ 3
81 × 10 × 10 = 8100 ÷ 3
So the answer is 2700.

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100 PTS help all information in pictures below

SVETLANKA909090 [29]

Answer:

Question 1: 11%

Question 2: 89%

Question 3: 43%

Question 4: 11%

Step-by-step explanation:

Looking at picture 1, we need to find the crossing point between -1.2 and 0.05. That has 0.1056, which is the same as 10.56%. 10.56% rounds to 11%, so C is our answer.

Picture 2 has the same chart, but we just need to find the inverse, since the inequality sign is flipped. 100 - 10.56 is 89.44%, which rounds to 89%, so D is the answer for Picture 2.

Picture 3 has two tables. 0.73 has 76.73% and -0.41 has 34.09%. Subtract 34.09% from 76.73% to get 42.64% That rounds to 43%, so A is the answer.

Picture 4 essentially has the same expression as Picture 2 (only the sign has switched): P(z ≥ 1.25). The meeting point is 89.44%. Now, subtract that from 100 to get 10.56%, which rounds to 11%. C is our answer for Picture 4.

I hope this helps you! ^w^

6 0

3 years ago

Read 2 more answers

Match the numerical expressions to their simplest forms.

Aloiza [94]

Answer:

$(a^6b^1^2)^\frac{1}{3}$ = $a^2b^4$

$\frac{(a^5b^3)^\frac{1}{2}}{(ab)^-^\frac{1}{2}}$ = $a^3b^2$

$(\frac{a^5}{a^-^3b^-^4})^\frac{1}{4}$ = $a^2b$

$(\frac{a^3}{ab^-^6})^\frac{1}{2}$ = $ab^3$

Step-by-step explanation:

Simplify each of the expressions:

$(a^6b^1^2)^\frac{1}{3}$

Distribute the exponent. Multiply the exponent of the term outside of the parenthesis by the exponents of the variable.

$(a^6b^1^2)^\frac{1}{3}$

$a^6^*^\frac{1}{3}b^1^2^*^\frac{1}{3}$

Simplify,

$a^2b^4$

Use a similar technique to solve this problem. Remember, a fractional exponent is the same as a radical, if the denominator is (2), then the operation is taking the square root of the number.

$\frac{(a^5b^3)^\frac{1}{2}}{(ab)^-^\frac{1}{2}}$

Rewrite as square roots:

$\frac{\sqrt{a^5b^3}}{\sqrt{(ab)}^-^1}$

A negative exponent indicates one needs to take the reciprocal of the number. Apply this here:

$\frac{\sqrt{a^5b^3}}{\frac{1}{\sqrt{ab}}}$

Simplify,

$\sqrt{a^5b^3}*\sqrt{ab}$

Since both numbers are under a radical, one can rewrite them such that they are under the same radical,

$\sqrt{a^5b^3*ab}$

Simplify,

$\sqrt{a^6b^4}$

Since this operation is taking the square root, divide the exponents in half to do this operation:

$a^3b^2$

$(\frac{a^5}{a^-^3b^-^4})^\frac{1}{4}$

Simplify, to simplify the expression in the numerator and the denominator, the base must be the same. Remember, the base is the number that is being raised to the exponent. One subtracts the exponent of the number in the denominator from the exponent of the like base in the numerator. This only works if all terms in both the numerator and the denominator have the operation of multiplication between them:

$(\frac{a^8}{b^-^4})^\frac{1}{4}$

Bring the negative exponent to the numerator. Change the sign of the exponent and rewrite it in the numerator,

$(a^8b^4)^\frac{1}{4}$

This expression to the power of the one forth. This is the same as taking the quartic root of the expression. Rewrite the expression with such,

$\sqrt[4]{a^8b^4}$

SImplify, divide the exponents by (4) to simulate taking the quartic root,

$a^2b$

$(\frac{a^3}{ab^-^6})^\frac{1}{2}$

Using all of the rules mentioned above, simplify the fraction. The only operation happening between the numbers in both the numerator and the denominator is multiplication. Therefore, one can subtract the exponents of the terms with the like base. The term in the denomaintor can be rewritten in the numerator with its exponent times negative (1).

$(a^3^-^1b^(^-^6^*^(^-^1^)^))^\frac{1}{2}$