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k0ka [10]
3 years ago
11

If the quotient of 18 3/5 is increased by 10 whats the solution?

Mathematics
1 answer:
andrew-mc [135]3 years ago
6 0

40 i belive but im not sure

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There are 283 students and Wiley school and 59 of them are in the sixth grade. What is the approximate percent of six graders at
Paladinen [302]
20% are in 6th grade
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3 years ago
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Find the common ratio 27,9,3,1,1/3
LenKa [72]

Answer:

1/3

Step-by-step explanation:

To find the common ratio, take the second term and divide by the first term

9/27 = 1/3

Check by dividing the third term by the second

3/9 = 1/3

and so forth

1/3 = 1/3

etc

The common ratio is 1/3

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3 years ago
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Two landscapers must mow a rectangular lawn that measures 100 feet by 200 feet. Each wants to mow no more than half of the lawn.
Citrus2011 [14]

The total area of the complete lawn is (100-ft x 200-ft) = 20,000 ft².
One half of the lawn is  10,000 ft².  That's the limit that the first man
must be careful not to exceed, lest he blindly mow a couple of blades
more than his partner does, and become the laughing stock of the whole
company when the word gets around.  10,000 ft² ... no mas !

When you think about it ... massage it and roll it around in your
mind's eye, and then soon give up and make yourself a sketch ...
you realize that if he starts along the length of the field, then with
a 2-ft cut, the lengths of the strips he cuts will line up like this:

First lap:
       (200 - 0) = 200
       (100 - 2) = 98
       (200 - 2) = 198
       (100 - 4) = 96    

Second lap:
       (200 - 4) = 196
       (100 - 6) = 94
       (200 - 6) = 194
       (100 - 8) = 92   

Third lap:
       (200 - 8) = 192
       (100 - 10) = 90
       (200 - 10) = 190
       (100 - 12) = 88 

These are the lengths of each strip.  They're 2-ft wide, so the area
of each one is (2 x the length). 

I expected to be able to see a pattern developing, but my brain cells
are too fatigued and I don't see it.  So I'll just keep going for another
lap, then add up all the areas and see how close he is:

Fourth lap:
       (200 - 12) = 188
       (100 - 14) = 86
       (200 - 14) = 186
       (100 - 16) = 84 

So far, after four laps around the yard, the 16 lengths add up to
2,272-ft, for a total area of 4,544-ft².  If I kept this up, I'd need to do
at least four more laps ... probably more, because they're getting smaller
all the time, so each lap contributes less area than the last one did.

Hey ! Maybe that's the key to the approximate pattern !

Each lap around the yard mows a 2-ft strip along the length ... twice ...
and a 2-ft strip along the width ... twice.  (Approximately.)  So the area
that gets mowed around each lap is (2-ft) x (the perimeter of the rectangle),
(approximately), and then the NEXT lap is a rectangle with 4-ft less length
and 4-ft less width.

So now we have rectangles measuring

         (200 x 100),  (196 x 96),  (192 x 92),  (188 x 88),  (184 x 84) ... etc.

and the areas of their rectangular strips are
           1200-ft², 1168-ft², 1136-ft², 1104-ft², 1072-ft² ... etc.

==> I see that the areas are decreasing by 32-ft² each lap.
       So the next few laps are 
               1040-ft², 1008-ft², 976-ft², 944-ft², 912-ft² ... etc. 

How much area do we have now:

             After 9 laps,    Area =   9,648-ft²
             After 10 laps,  Area = 10,560-ft².

And there you are ... Somewhere during the 10th lap, he'll need to
stop and call the company surveyor, to come out, measure up, walk
in front of the mower, and put down a yellow chalk-line exactly where
the total becomes 10,000-ft².   


There must still be an easier way to do it.  For now, however, I'll leave it
there, and go with my answer of:  During the 10th lap.

5 0
3 years ago
1. Make sure to respond with complete sentences! Show all work please:)
tino4ka555 [31]

Explanation:

The numerator of the rational exponent will be the product of the exponents inside and outside the radical: 5·7=35. The denominator of the rational exponent will be the index of the radical: 6. Then the equivalent expression is x^(35/6)

7 0
3 years ago
IN A CLASS OF 30 STUDENTS 13 OF THEM ARE BOYS WHAT PERCENTAGE ARE GIRLS?
mestny [16]
Class of students - number of students that are boys = numbers of students that are girls

30 - 13 = 17

To change the number of students that are girls into percentage...

17/1 * 1/100 = 17/100

17/100 in a % form = 17%

The percentage of girls in the class is 17%

5 0
3 years ago
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