The axis of symmetry of the quadratic equation y = 2x^2 + 3 is x = 0
<h3>How to determine the axis of symmetry?</h3>
The equation is given as:
y = 2x^2 + 3
Differentiate the above equation with respect to x
y' = 4x + 0
This gives
y' = 4x
Set the equation to 0
4x = 0
Divide both sides by 4
x = 0
Hence, the axis of symmetry is x = 0
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there is no solution if the equation are put together but there is if they are done alone
first question and second question
The answer is in the picture above please mark me brainliest :)
I believe the flagpole is 24ft
Use these variables to make an equation-
y is the total amount.
$50 is where you start charging(y intercept, variable b).
x is how many visits Marsha made.
The equation can be in slope-intercept form (y=mx+b)-
$144=$2x+50
Solve for x using inverse operations.
Subtract 50 from both sides-
144-50=2x+50-50
94=2x
Divide 2 from both sides-
94/2=2/2
x=47
Marsha made 47 visits to the health club.
Add all the like terms
3b + b = b(3 + 1) = 4b
So, 3b + b + 6 = 4b + 6