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MrRissso [65]
2 years ago
10

Evaluate the following expression by applying the appropriate properties (24) 3 (31.7)/ 172

Mathematics
1 answer:
ale4655 [162]2 years ago
7 0

−3/7×14/15×7/12×(−30/35)

=(−3/7×14/15)×(7/12×−30/35)

On further calculation, we get

=−2/5×−1/2

We get,

=1/5.

Property 1:

If a/b is a rational number and m is a non-zero integer then a/b =(a*m)/(b*m). In other words, we can say that the rational number remains unaltered if we multiply both the numerator and denominator with the same integer. Ex: 2/3 = 2*2/3*2 = 4/6, 2*3/3*3 = 6/9, 2*4/3*4 = 8/12.

Math Properties

Commutative Property.

Associative Property.

Distributive Property.

Identity Property.

Inverse Property.

Learn more about appropriate properties at

brainly.com/question/23576294

#SPJ4

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what is the first term of a geometric sequence in which the second term is 6 and the fourth term is 54
IRISSAK [1]
For a geometric sequence:
U_{n} = a * r^{n - 1}
U_{n} = the nth term, i.e. U₂ is the second term, U₃ is the third term, etc.
a = first term (U₁)
r = multiplier
n = number corresponding to the postion of the nth term in the sequence, e.g. for U₂, n = 2, for U₃, n = 3

According to the information:
U₂ = 6
U₄ = 54
So:
U_{2} = a * r^{(2) - 1} = 6 \\\\ a * r^{1} = 6 \\\\ ar = 6 \\
U_{4} = a * r^{(4) - 1} = 54 \\\\ a * r^{3} = 54 \\\\ ar^{3} = 54
Now, we have two equations in terms of a and r;
We can work out a by first working out r;
If we let the U₂ eq'n be [1] and the U₄ eq'n be [2];
Then, we do [2] ÷ [1] to cancel out the a and get an equation with only r that we are able to solve and then just solve it, like so:
\frac{ar^{3}}{ar} =  \frac{54}{6} \\\\ r^{2} = 9 \\\\ r = 3
Note: r has to be 3, and not -3, as the two given terms of the sequence tell us that the terms of the sequence will get bigger from each term to the next so r has to be above 1.

Now that we know r, we can sub it back into either [1] or [2] and solve for a, Its quicker and easier to sub it into [1] as we have no powers greater than 1 and we have smaller numbers to deal with (but you would get the same value of a either way), so:
U₂ = ar = 6
a(3) = 6
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5 0
3 years ago
What are the values of x and y
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E 10 12

x=18*5)14. x=40/4. x=10. y=(15*4)/5 y=60/5 y=12.

resposta : 10 e 12

4 0
3 years ago
How to write the number two hundred billion in half
Scorpion4ik [409]
<span>Given number: Two hundred billion in half, how to write this one in standard form
let us first simplify each statement:
=> two hundred billion = 200 000 000 000
=> in half meaning = half of the given number or divide the given number by 2 to get the answer
=> 200 000 000 000 / 2
Show, the ½ of two hundred billion in standard form
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</span>



6 0
3 years ago
Which congruence theorems can be used to prove ΔABR ≅ ΔACR? Select three options.
sergejj [24]

Answer:

1. HL

2. SAS

3. SSS

Step-by-step explanation:

Triangles ABR and ACR share side AR (hypotenuse of two right triiangles).

Angles ABR and ACR are right angles.

Sides AB and AC are congruent.

Sides BR and CR are congruent.

1. You can use HL theorem, because two triangles have congruent pair of legs and congruent hypotenuses.

2. You can use SAS theorem, because two triangles have two pairs of congruent legs and a pair of included right angles between these legs.

3. You can use SSS theorem, because two triangles have two pairs of congruent legs and  congruent hypotenuses.

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