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bearhunter [10]
3 years ago
11

Solve the system by graphing

Mathematics
2 answers:
julia-pushkina [17]3 years ago
8 0
The graph shows the solution to be (x, y) = (-1, 3).

anzhelika [568]3 years ago
6 0

graph each equations and your answer is where it intersects and in this case that would be (-1,3)

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The temperature at 8:00 am was -10ºF. It rose 15º by noon. At 7:00 pm, the temperature dropped 25º. What was the temperature at
notsponge [240]

Answer:

The answer would be -30°F

6 0
2 years ago
PLEASE ANSWER QUICKLY!!! La'Shaun is knitting a scarf for her brother. It took her 1/3 hour to knit 1/2 of a scarf how fast is L
saveliy_v [14]

Answer:

Fast

Step-by-step explanation:

1/3 hour is 20 minutes

so that means it will take her 40 minutes to make the whole scarf.

3 0
2 years ago
BRAINLIEST!!! PLEASE HELP..!!
amm1812

Answer:

2nd choice:

x int: 11/6

y int: 11/2

Step-by-step explanation:

put 6x + 2y = 11 into y = mx+b form to find y intercept. (b stands for the y int)

you get y = -3x + 11/2.

now you can graph with this.

plug 0 in for y and solve for x to find x int

0 = -3x + 11/2 then solve

7 0
3 years ago
A rock outcrop was found to have 95.82% of its parent U- 238 isotope remaining. Approximate the age of the outcrop. The half-lif
mixer [17]

Answer:

A) 277 million years

Step-by-step explanation:

Here, decay of U-238 is first order reaction. (since most of the nuclear decays are first order).

so, the equation t = \frac{1}{k} × ln(\frac{A(0)}{A})

where, t = time from start of reaction

           k = reaction constant

           A(0) = initial concentration; A = present concentration.

     ⇒ 4.5 billion = 4500 million years = \frac{1}{k}× ln2.

Now, given 95.82% of parent U-238 isotope is left.

⇒ t = \frac{1}{k} × ln(\frac{A(0)}{A})

  t = \frac{4500}{ln2} × ln(\frac{100}{95.82})

⇒ t ≅ 277 million years.

5 0
3 years ago
See image for question.​
Ostrovityanka [42]

Answer:

  • See below

Step-by-step explanation:

#3

  • P(A) = 3/8
  • P(B) = 2/7

(i)

  • P(A and B) = P(A) * P(B) = 3/8*2/7 = 3/28

(ii)

  • P(A or B) = P(A) + P(B) - P(A and B) = 3/8 + 2/7 - 3/28 = 1/56(21 + 16 - 6) = 31/56

(iii)

  • P(not A and not B) = P(not A) * P(not B) = (1 - 3/8)*(1 - 2/7) = 5/8*5/7 = 25/56

<u>Another way:</u>

  • P(not A and not B) = 1 - P(A or B) = 1 - 31/56 = 25/56

#4

Outcomes with two fair coins: TT, TH, HT, HH

Outcomes with normal dice: 1 to 6

a)

  • P(odd number) = 3/6 = 1/2

b)

  • P(two heads and an even number) = 1/4*3/6 = 1/8

c)

  • P(head and tail) = 1/2
  • P(prime) = 3/6 = 1/2 (primes are 2, 3 and 5)
  • P(head, tail and prime) = 1/2*1/2 = 1/4

d)

  • P(two tails and odd number) = 1/4*3/6 = 1/8
4 0
3 years ago
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