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Dafna1 [17]
3 years ago
8

The radius of a sphere is 11 cm.what is the surface area of the sphere? Round to the nearest tenth.

Mathematics
1 answer:
Vanyuwa [196]3 years ago
8 0

Answer:

The answer is

<h2>1520.5 cm²</h2>

Step-by-step explanation:

Surface area of a sphere is given by

S = 4πr²

where r is the radius

From the question r = 11cm

So the surface area of the sphere is

4π(11)²

= 4(121)π

= 484π

= 1520.5308

Which is

1520.5 cm² to the nearest tenth

Hope this helps you

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5 0
3 years ago
Please help!
crimeas [40]

Answer:

The zeros are:

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  • The function has three distinct real zeros.

Hence, option (B) is true.

Step-by-step explanation:

Given the expression

h\left(x\right)=\left(x-4\right)^2\left(x^2-7x+\:10\right)

Let us determine the zeros of the function by putting h(x) = 0 and solving the expression

0=\left(x-4\right)^2\left(x^2-7x+10\right)

switch sides

\left(x-4\right)^2\left(x^2-7x+10\right)=0

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so

\left(x-4\right)^2\left(x-2\right)\left(x-5\right)=0

Using the zero factor principle

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so

x-4=0\quad \mathrm{or}\quad \:x-2=0\quad \mathrm{or}\quad \:x-5=0

x =4, x=2, x = 5

Thus, the zeros are:

x =4, x=2, x = 5

It is clear that there are three zeros and all the zeros are distinct real numbers.

Therefore,

  • The function has three distinct real zeros.

Hence, option (B) is true.

4 0
3 years ago
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LUCKY_DIMON [66]

Answer:

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x=103°

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-----------

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