Find two solutions of y = 2x +5 (Use x= 0 and x=1 to find your solutions) *

A model of a building is 18 inches tall. If the building is really 678 feet tall, how tall is a window that is 1/9 in on the mod

ipn [44]

Answer:

50.2in or 4.2ft

Step-by-step explanation:

This is a problem about proportions so I generally set up my problems like below. I just set some variable here to make it easier to refer back to the measurements for each. You don't have to do this, I am just showing it for clarity. I will convert everything to inches too. We need to find the real window height.

Mb = model building = 18in

Mw= model window = $\frac{1}{9}$ in

Rb = real building = 678ft = 8136in

Rw = real window = ?

$\frac{Mw}{Mb}$ = $\frac{Rw}{Rb}$

$\frac{1/9}{18}$ = $\frac{Rw}{8136}$

$\frac{1}{9*18}$ = $\frac{Rw}{8136}$

$\frac{1}{162}$ = $\frac{Rw}{8136}$

$\frac{1*8136}{162}$ = $\frac{8136*Rw}{8136}$

$\frac{8136}{162}$ = Rw

$\frac{452}{9}$ = Rw

Rw ≈ 50.2in ≈ 4.2ft

5 0

2 years ago

First you to find the worksheet and download it<br> plase I need help

Goshia [24]

Answer:

a) The horizontal asymptote is y = 0

The y-intercept is (0, 9)

b) The horizontal asymptote is y = 0

The y-intercept is (0, 5)

c) The horizontal asymptote is y = 3

The y-intercept is (0, 4)

d) The horizontal asymptote is y = 3

The y-intercept is (0, 4)

e) The horizontal asymptote is y = -1

The y-intercept is (0, 7)

The x-intercept is (-3, 0)

f) The asymptote is y = 2

The y-intercept is (0, 6)

Step-by-step explanation:

a) f(x) = $3^{x + 2}$

The asymptote is given as x → -∞, f(x) = $3^{x + 2}$ → 0

∴ The horizontal asymptote is f(x) = y = 0

The y-intercept is given when x = 0, we get;

f(x) = $3^{0 + 2}$ = 9

The y-intercept is f(x) = (0, 9)

b) f(x) = $5^{1 - x}$

The asymptote is fx) = 0 as x → ∞

The asymptote is y = 0

Similar to question (1) above, the y-intercept is f(x) = $5^{1 - 0}$ = 5

The y-intercept is (0, 5)

c) f(x) = 3ˣ + 3

The asymptote is 3ˣ → 0 and f(x) → 3 as x → ∞

The asymptote is y = 3

The y-intercept is f(x) = 3⁰ + 3= 4

The y-intercept is (0, 4)

d) f(x) = 6⁻ˣ + 3

The asymptote is 6⁻ˣ → 0 and f(x) → 3 as x → ∞

The horizontal asymptote is y = 3

The y-intercept is f(x) = 6⁻⁰ + 3 = 4

The y-intercept is (0, 4)

e) f(x) = $2^{x + 3}$ - 1

The asymptote is $2^{x + 3}$ → 0 and f(x) → -1 as x → -∞

The horizontal asymptote is y = -1

The y-intercept is f(x) = $2^{0 + 3}$ - 1 = 7

The y-intercept is (0, 7)

When f(x) = 0, $2^{x + 3}$ - 1 = 0

$2^{x + 3}$ = 1

x + 3 = 0, x = -3

The x-intercept is (-3, 0)

f) $f(x) = \left (\dfrac{1}{2} \right)^{x - 2} + 2$

The asymptote is $\left (\dfrac{1}{2} \right)^{x - 2}$ → 0 and f(x) → 2 as x → ∞

The asymptote is y = 2

The y-intercept is f(x) = $f(0) = \left (\dfrac{1}{2} \right)^{0 - 2} + 2 = 6$

The y-intercept is (0, 6)

7 0

2 years ago

7) A coin is tossed three times, with 'heads' or 'tails' recorded after each toss. The number of possible outcomes for this expe

makkiz [27]

2^3 = 8 outcomes possible.

5 0

3 years ago

If someone could please walk me through on how to answer this.

Elis [28]

To isolate c means to separate it completely on one side of the equals sign.

To isolate variables, you apply opposite operations.

In E = mc², m and c are being multiplied together. To separate them, you divide by the variable you want to get rid of. However, you must do this to both sides of the equation always. Whatever you do to one side of the equation you must do to the other side as well. This is so the equation remains true.

Since we want to isolate c, we'll start by dividing both sides by m.

E = mc²

E/m = mc²/m

E/m = c² -- The m's cancel as 1

Now we have c squared. The opposite of squaring something is taking its square root. Take the square root of each side.

E/m = c²

√(E/m) = √(c²)

√(E/m) = c -- Opposite operations cancel each other out

And you've isolated c!

Answer:

c = √(E/m)

3 0

3 years ago

16. If the base of parallelogram is 10 cm and its corresponding height is 5

lara [203]

Answer:

50 cm²

The answer is that because the area of a parallelogram is height × width.

height = 10cm

width = 5 cm

10 × 5= 50cm²

7 0

3 years ago