Answer:
Part 1) The exponential function is equal to ![y=1,350(0.95)^{x}](https://tex.z-dn.net/?f=y%3D1%2C350%280.95%29%5E%7Bx%7D)
Part 2) The population in 2010 was
Step-by-step explanation:
Part 1) Write an exponential decay function that models this situation
we know that
In this problem we have a exponential function of the form
![y=a(b)^{x}](https://tex.z-dn.net/?f=y%3Da%28b%29%5E%7Bx%7D)
where
y ----> the fish population of Lake Collins since 2004
x ----> the time in years
a is the initial value
b is the base
we have
![a=1,350\ fish](https://tex.z-dn.net/?f=a%3D1%2C350%5C%20fish)
![b=(100\%-5\%)=95\%=0.95](https://tex.z-dn.net/?f=b%3D%28100%5C%25-5%5C%25%29%3D95%5C%25%3D0.95)
substitute
----> exponential function that represent this scenario
Part 2) Find the population in 2010
we have
so
For ![x=(2010-2004)=6\ years](https://tex.z-dn.net/?f=x%3D%282010-2004%29%3D6%5C%20years)
substitute
Answer:
Well the answer is 13.3 so 13 years old
Step-by-step explanation:
(F,Y) = (63,21)
Y3=F so F/3=y
so
F= 40
Y=?
40/3=Y
40/3=13.3
Answer:
36.72
Step-by-step explanation:
Take 60% of 61.20. That is the markup.
60% * 61.20 = 60/100 * 61.2 = 3672/100 = 36.72
The markup is 36.72
Answer:
C (48)
explanation:
firstly, divide 384 by 80. This gives you 4.8. So, since 10 out of every 80 students are left handed we have to times 4.8 by 10 which gives you 48.
Uhm i don't understand ;(!!