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Romashka [77]
4 years ago
6

a highschool computer club has 15 members . how many different ways can they choose a president and vice president

Mathematics
1 answer:
Nataliya [291]4 years ago
3 0
Answer=210 ways

Okay. I'm not entirely sure this is the BEST way to solve for this answer, but nonetheless, I'll show how I would solve the equation.

First, lets look at the probability of the two options happening. The probability of one of the 15 members becoming president is 1/15. Then, since one student is already being used for the spot of president, the odds of another student becoming vice president is 1/14.

\frac{1}{15} * \frac{1}{14} = \frac{1}{210}

From this, we know that there are 210 options for the positions of president and vice president total (since 210 represents the whole).

So they can choose the president and vice president 210 different ways
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For the answer to the question above, the easiest way to determine is changing every runner's speed into the same unit.

<span>First = 10 m/s </span>

<span>Second = 10 miles/min = 16090.34 / 60 m/s (As 1 mile = 1609.34 meter and 1 min = 60 sec) </span>
<span>Second = 260.82 m/s </span>

<span>Third = 10 cm/hr = 10*(0.01)/60*60 (As 1 cm = 0.01 m and 1 hr = 60*60 sec) </span>
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<span>Fourth = 10 km/sec = 10*1000 m/s (As 1 km = 1000 m and time is already in sec) </span>
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3 years ago
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An experiment consists of ranomly drawing three cards in succession without replacement from a standard deck of 52 cards. Let A
nadya68 [22]

Answer:

0.0045248 ;

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Step-by-step explanation:

Number of Kings in deck = 4

Total number of cards in deck = 52

Picking without replacement :

A = King on first draw :

P(A) = 4 / 52

A = King on 2nd draw :

P(B) = 3 / 51

A = King on 3rd draw :

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P(A n B) = 4/52 * 3/51 = 12 / 2652 = 0.0045248

2.) P(A u B) = P(A) + P(B) - P(AnB)

P(AuB) = 4/52 + 3/51 - 0.0045248 = 0.1312218

3.) P(A ∩ B ∩ C) = P(A) * P(B) * P(C)

P(A ∩ B ∩ C) = 4/52 * 3/51 * 2/50 = 0.0001809

4.) P(A U B U C) =

P(A) + P(B) + P(C) - P(AnB) - P(AnC) - P(BnC) - P(AnBnC)

P(AnC) = P(A) * P(C) = 4/52 * 2/50 = 0.0030769

P(BnC) = P(B) * P(C) = 3/51 * 2/50 = 0.0023529

4/52 + 3/51 + 2/50 - 0.0045248 - 0.0030769 - 0.0023529 + 0.0001809 = 0.1659729

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3 years ago
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Step-by-step explanation:

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Answer:

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