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Sloan [31]
3 years ago
12

the track at Morgans School is 1/4 mile long. he runs 8 laps around the track how far did Morgan run?

Mathematics
2 answers:
jarptica [38.1K]3 years ago
3 0
8 * 1/4 = 8/4 = 2 miles <==
Elis [28]3 years ago
3 0
If we want to know how many miles Morgan ran, we need to multiply the distance of 1 lap by the number of laps.

8 laps x 1/4 mile per lap = 2 miles
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Rudiy27

Answer:

10.5, 10\frac{1}{2}, or \frac{21}{2}

Step-by-step explanation:

To solve, you can use a variable (x) to represent the width.

The equation for area is A=L×W

So the Area is 820 and the length is 78.

820= 78w

Isolate the variable to solve.

w=10.5128....

If you round, it will be 10.5

10.5 as a fraction is 10\frac{1}{2} or \frac{21}{2}

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Write the prime factorization of each number using exponents:<br><br> 56 = ?<br> 68 = ?
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Same thing for 68: factored = 2 x 34 = 2 x 2 x 17
2^2 x 17 is the answer.
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3 years ago
Which of the following inequalities represents a number y that is less than 4 but greater than -1
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Four is greater than y, and -1 is less than y

4 > y <  - 1

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3 years ago
K plus 22 for khan academy
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That’s the question ?
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3 years ago
Eric's class consists of 12 males and 16 females. If 3 students are selected at random, find the probability that they
Reptile [31]

Answer:

The probability that all are male of choosing '3' students

P(E) = 0.067 = 6.71%

Step-by-step explanation:

Let 'M' be the event of selecting males n(M) = 12

Number of ways of choosing 3 students From all males and females

n(M) = 28C_{3} = \frac{28!}{(28-3)!3!} =\frac{28 X 27 X 26}{3 X 2 X 1 } = 3,276

Number of ways of choosing 3 students From all males

n(M) = 12C_{3} = \frac{12!}{(12-3)!3!} =\frac{12 X 11 X 10}{3 X 2 X 1 } =220

The probability that all are male of choosing '3' students

P(E) = \frac{n(M)}{n(S)} = \frac{12 C_{3} }{28 C_{3} }

P(E) =  \frac{12 C_{3} }{28 C_{3} } = \frac{220}{3276}

P(E) = 0.067 = 6.71%

<u><em>Final answer</em></u>:-

The probability that all are male of choosing '3' students

P(E) = 0.067 = 6.71%

3 0
4 years ago
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