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Rufina [12.5K]
2 years ago
6

Given: Cosine (x minus y)

Mathematics
1 answer:
Lady bird [3.3K]2 years ago
6 0

The required steps that complete the proof are:

Step 1: Cofunction Identity

Step 5: Sine Difference Identity

Step 6: Cofunction Identity

Step 7: Cosine Function Is Even, Sine Function Is Odd

<h3>Trigonometry identity</h3>

Given the cosine function expressed as:

  • cos(x - y)

The first step is to apply the cofunction identity as shown:

  • Step 1: Cofunction Identity

cos(90 - x) = sin x

cos(x - y) = sin (90-(x-y))

  • Step 5: Sine Difference Identity

For the fifth step, you will apply the sine difference identity.

  • Step 6: Cofunction Identity

To get the sixth step, you will apply the Cofunction Identity on the result in the fifth step.

The final step 7 will be

  • Step 7: Cosine Function Is Even, Sine Function Is Odd

Learn more on trigonometry identity here: brainly.com/question/24496175

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Random samples of students were compared to see whether or not there was a difference in the proportion favoring the university'
Nimfa-mama [501]

Answer:

There is enough evidence to support the claim that there is a significant difference in the proportion of residents and commuters who prefer the switch.

Step-by-step explanation:

This is a hypothesis test for the difference between proportions.

The claim is that there is a significant difference in the proportion of residents and commuters who prefer the switch.

Then, the null and alternative hypothesis are:

H_0: \pi_1-\pi_2=0\\\\H_a:\pi_1-\pi_2\neq 0

The significance level is 0.05.

The sample 1 (residents), of size n1=200 has a proportion of p1=0.4.

p_1=X_1/n_1=80/200=0.4

The sample 2 (conmuters), of size n2=200 has a proportion of p2=0.6.

p_2=X_2/n_2=120/200=0.6

The difference between proportions is (p1-p2)=-0.2.

p_d=p_1-p_2=0.4-0.6=-0.2

The pooled proportion, needed to calculate the standard error, is:

p=\dfrac{X_1+X_2}{n_1+n_2}=\dfrac{80+120}{200+200}=\dfrac{200}{400}=0.5

The estimated standard error of the difference between means is computed using the formula:

s_{p1-p2}=\sqrt{\dfrac{p(1-p)}{n_1}+\dfrac{p(1-p)}{n_2}}=\sqrt{\dfrac{0.5*0.5}{200}+\dfrac{0.5*0.5}{200}}\\\\\\s_{p1-p2}=\sqrt{0.0013+0.0013}=\sqrt{0.0025}=0.05

Then, we can calculate the z-statistic as:

z=\dfrac{p_d-(\pi_1-\pi_2)}{s_{p1-p2}}=\dfrac{-0.2-0}{0.05}=\dfrac{-0.2}{0.05}=-4

This test is a two-tailed test, so the P-value for this test is calculated as (using a z-table):

P-value=2\cdot P(z

As the P-value (0.00008) is smaller than the significance level (0.05), the effect is significant.

The null hypothesis is rejected.

There is enough evidence to support the claim that there is a significant difference in the proportion of residents and commuters who prefer the switch.

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4 years ago
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