The volume of Kuroshio Sea rank is 9450 cubic meters, if the sea tank is 27m long, 35m wide and 10m deep.
Step-by-step explanation:
The given is,
Kuroshio Sea tank is 27m long, 35m wide and 10m deep.
Step:1
Sea tank looks like a rectangular prism,
Formula to calculate the volume of rectangular prism,
.............................(1)
Where, w - Width of the rectangular prism
h - Height or depth of the rectangular prism
l - Length of the rectangular prism
From given,
w = 35 meters
l = 27 meters
h = 10 meters
Equation (1) becomes,



Volume of the sea tank, V = 9450 Cubic meters
Result:
The volume of Kuroshio Sea rank is 9450 cubic meters, if the sea tank is 27m long, 35m wide and 10m deep.
Answer:
2160 cm³/hour
Step-by-step explanation:
By default, we know that the volume of a cube is given as s³
Thus, the Volume function, V = s³
When we differentiate with respect to time we have
dV/dt = 3s² (ds/dt), where ds/dt = 0.2
Then we go ahead and substitute all the given parameters
dV/dt = 3 x 60 x 60 x 0.2
dV/dt = 10800 * 0.2
dV/dt = 2160 cm³/hour
This means that the volume decreases by a rate of 2160 cm³/hour at the instant its edge is 60 cm
To know if there is a perfect square you gotta see if there is a minus sign before the second coefficient and when you square the second coefficient divided by 2 you should get the third coefficient
Answer:
The answer to your question is 11.4 units
Step-by-step explanation:
Data
A (-3, -1)
B ( 0, 3)
C ( 1, 2)
Perimeter = ?
Formula
d = 
Process
1.- Find the length between the points
dAB = 
dAB = 
dAB = 
dAB = 
dAB = 5
dBC= 
dBC = 
dBC = 
dBC = 
dAC = 
dAC = 
dAC = 
dAC = 
dAC = 5
2.- Perimeter
P = AB + BC + AC
P = 5 +
+ 5
P = 10 + 
P = 10 + 1.42
P = 11.4
72 in2 because you add the area of everything